E-field on a spherical shell with a hole

In summary, the problem at hand involves finding the electric field at the center of a small circular hole in a uniformly charged spherical shell. The key is to use the approximation that the hole is flat and to superimpose the disk on the shell. This can be done using Gauss's Law and exploiting the symmetries of the field. The field of a uniformly charged spherical shell can be calculated using several methods, and in this case, taking the average of the fields just inside and just outside the shell may be useful due to the discontinuity at the surface.
  • #1
semc
368
5
A uniformly charged spherical shell with surface charge density [tex]\sigma[/tex] contains a circular hole in its surface. the radius of the hole is small compared with the radius of the sphere. what is the electric field at the center of the hole?

I only know this question requires superposition of the sphere and the circle but how do we do it? I thought we can only find the e-field at some point due to a charge? Are we suppose to consider infinitesimal charge on the sphere and do a integration over the entire surface to find the e-field on the cavity? Also, does the size of the hole affect the answer?
 
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  • #2
The key here is that the radius of the hole is small compared to the radius of the sphere. Using that approximation, it is reasonable to assume that the hole is more or less flat.

Do you know how to calculate the field at the center of a uniformly charged disk, carrying surface charge density [itex]-\sigma[/itex]? What do you get when you superimpose such a disk on a much larger spherical shell carrying surface charge density [itex]+\sigma[/itex]?
 
  • #3
How do you do that? I only know how to calculate the field at a distance surrounding a charge. I suppose we have to use Gauss's law?
 
  • #4
If you don't know how to calculate the field of a flat circular disk, at a point on its axis or at its center, you need to open your textbook. That calculation is done as an example in almost every introductory EM text I can recall seeing.
 
  • #5
Actually I meant how do you calculate the field of the solid sphere. Do you mean calculating the field on the surface of the sphere as if there is a charge at the center of the sphere?
 
  • #6
There are several methods for finding the field of a uniformly charged spherical shell. The easiest method is to use Gauss' Law...can you think f what symmetries a field produced by a uniformly charged spherical shell would have, and a Gaussian surface you can use to exploit those symmetries?

You will find that the field is discontinuous at the surface, and so you might consider using the average of the fields just inside and just outside the shell for this problem, since when the hole is present, there will be no discontinuity there.
 

1. What is an E-field on a spherical shell with a hole?

An E-field on a spherical shell with a hole refers to the electric field created by a point charge located outside the spherical shell, passing through the hole in the shell.

2. How is the E-field on a spherical shell with a hole calculated?

The E-field on a spherical shell with a hole can be calculated using the formula E = kq/r^2, where k is the Coulomb's constant, q is the charge of the point charge, and r is the distance from the point charge to the center of the spherical shell.

3. How does the presence of a hole affect the E-field on a spherical shell?

The presence of a hole in the spherical shell does not affect the magnitude of the E-field, but it changes the direction of the field at the points on the shell's surface near the hole. This is because the field lines will be directed towards the point charge passing through the hole.

4. Can the E-field on a spherical shell with a hole be zero?

Yes, the E-field on a spherical shell with a hole can be zero at certain points on the shell's surface. This occurs when the point charge is located at the center of the shell, resulting in a cancellation of the electric field due to the symmetry of the system.

5. How does the size of the hole affect the E-field on a spherical shell?

The size of the hole does not affect the magnitude of the E-field, but it does impact the direction of the field at different points on the shell's surface. A larger hole will result in a larger area of the shell's surface where the field lines will be directed towards the point charge, while a smaller hole will have a smaller impact on the direction of the field.

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