I Early opaque universe - why little proton-photon scattering?

AI Thread Summary
The early universe was opaque primarily due to photon scattering off free electrons, as this process is significantly more efficient than scattering off protons. The scattering cross section for photons interacting with electrons is much larger due to their lower mass, leading to a suppression factor of about a million for protons. This phenomenon is explained by the classical interpretation of Thomson scattering, where the acceleration of charged particles by electromagnetic radiation is inversely proportional to their mass. Consequently, electrons experience greater acceleration and radiation of energy compared to protons. Overall, the mass difference between electrons and protons plays a crucial role in the scattering dynamics of photons in both the early universe and within stars.
Lapidus
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I read many times that the early universe was opaque foremost because of the scattering of photons off free electrons (Thomson scattering). Why is the scattering off free protons not equally important?

Btw, the same they say about stars. Photons within stars need a very long time to get out of the star because of scattering off the free electrons. Again, why not protons?

thanks!
 
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The Thomson scattering cross section is proportional to m^{-2}, and so scattering off the much heavier protons is suppressed by a factor of a million relative to scattering off electrons.
 
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Thanks!

And why is that so? Is there a simple physical argument behind this (curious) effect that photons scatter off particle with less mass with higher probability than they do with more massive particles?

My guess is that in Compton scattering the virtual particle in the Feynman graph is massive (an electron). So the more massive the propagator particle, the smaller the amplitude. Wrong?
 
OR is it simply because the Compton wavelength is much smaller for protons than for electrons?
 
It's best to think about Thomson scattering as a classical phenomenon, in which instead of photons bouncing of particles, one has a charged particle being accelerated by incident electromagnetic radiation and in turn radiating electromagnetic energy -- the scattered light. The power emitted is proportional to the time-averaged squared acceleration of the particle, which is itself proportional to m^{-2} from Newton's 2nd law. This makes sense: electrons are more vigorously jiggled than protons by the electromagnetic radiation.
 
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https://en.wikipedia.org/wiki/Recombination_(cosmology) Was a matter density right after the decoupling low enough to consider the vacuum as the actual vacuum, and not the medium through which the light propagates with the speed lower than ##({\epsilon_0\mu_0})^{-1/2}##? I'm asking this in context of the calculation of the observable universe radius, where the time integral of the inverse of the scale factor is multiplied by the constant speed of light ##c##.
Why was the Hubble constant assumed to be decreasing and slowing down (decelerating) the expansion rate of the Universe, while at the same time Dark Energy is presumably accelerating the expansion? And to thicken the plot. recent news from NASA indicates that the Hubble constant is now increasing. Can you clarify this enigma? Also., if the Hubble constant eventually decreases, why is there a lower limit to its value?

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