Easy differential equation but i am stuck

fufufu
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Homework Statement


What is the general solution of tv' + v = 0?
book says it is v(t) = c/t but i don't see how
i tried to solve like this:

v' + (1/t)v = 0

p(t) = 1/t
P(t) = Ln(t)

y = e^ln(t) + c

= t + e^c

please help,thanks



Homework Equations





The Attempt at a Solution

 
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what is y?

your first equation is separable, write v'=dv/dt, then move all terms with a v to the LHS and all terms with a t to the RHS then integrate both sides
 
fufufu said:

Homework Statement


What is the general solution of tv' + v = 0?
book says it is v(t) = c/t but i don't see how
i tried to solve like this:

v' + (1/t)v = 0

p(t) = 1/t
P(t) = Ln(t)

y = e^ln(t) + c
This isn't right. What you're doing by calculating ##e^{\int p(t)\,dt}## is finding an integrating factor, not the solution to the differential equation. Check your textbook to see what you're supposed to do with this factor.

(Or solve the problem the way lanedance suggested.)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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