Easy Guide: Solving Integral (sin x)/x dx from 0 to pi | Tips & Tricks

  • Thread starter Thread starter lueffy
  • Start date Start date
  • Tags Tags
    Integral
Click For Summary

Homework Help Overview

The discussion revolves around the integral of (sin x) / x from 0 to pi, a topic within calculus that involves improper integrals and series expansions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the possibility of using integration by parts and series expansion for the integral. Questions arise about the validity of different integration methods and the nature of the integral itself.

Discussion Status

Some participants have provided insights into series expansion as an approach, while others express confusion regarding the integration process and the limitations of certain methods. There is an ongoing exploration of terminology related to integration techniques.

Contextual Notes

Participants note the complexity of the integral and the limitations of standard methods taught in calculus, indicating a potential gap in foundational understanding of advanced integration techniques.

lueffy
Messages
9
Reaction score
0
How to solve the integral (sin x) / x dx
from 0 to pi (3.14...)

at first i thought this could be easily done with partial integration,
but on the contrary, I'm still dying here, trying to solve it...:frown:
 
Last edited:
Physics news on Phys.org
Nope. It cannot be done by Integration by parts (note that it's Integration by parts and not Partial integration). One way to do it is to notice that:
\sin x = x - \frac{x ^ 3}{3!} + \frac{x ^ 5}{5!} + ... = \sum_{k = 0} ^ {\infty} (-1) ^ {k} \frac{x ^ {2k + 1}}{(2k + 1)!}
So:
\frac{\sin x}{x} = 1 - \frac{x ^ 2}{3!} + \frac{x ^ 4}{5!} + ... = \sum_{k = 0} ^ {\infty} (-1) ^ {k} \frac{x ^ {2k}}{(2k + 1)!}
Now, just integrate both sides, can you go from here? :)
\int \frac{\sin x}{x} dx = \int \left( \sum_{k = 0} ^ {\infty} (-1) ^ {k} \frac{x ^ {2k}}{(2k + 1)!} \right) dx = ?
 
Last edited:
Wow, thanks man, but that's just beyond my calculus class...
But, whew, it really wasn't an easy one...
Thanks for telling me about the "partial integration" part...

But how you suppose to do the latter integration?
an integral with sigma inside? i thought that integral sign is somewhat related to sigma, but only for continuous distribution of the partition, from the definition of Riemann's integrals...
 
Eh, and may i ask you one more thing?
Why the integral can't be done with integration by parts?
i mean, this far i just know few methods to solve integrals, that is substituting, integration by parts, and with trig subs...
I heard there's a lot of integral types, which can't be done with only the very few methods that I've mentioned above...

Thanks for the help, I'm greatly appreciated it...
 
(note that it's Integration by parts and not Partial integration).

Nonsense...
 
lueffy said:
Wow, thanks man, but that's just beyond my calculus class...
But, whew, it really wasn't an easy one...
Thanks for telling me about the "partial integration" part...

But how you suppose to do the latter integration?
an integral with sigma inside? i thought that integral sign is somewhat related to sigma, but only for continuous distribution of the partition, from the definition of Riemann's integrals...
This is correct. Just do it like you are integrating x dx, or (x2 + 3x) dx, ...
\int \frac{\sin x}{x} dx = \sum_{k = 0} ^ \infty \left( (-1) ^ k \frac{x ^ {2k + 1}}{(2k + 1) (2k + 1)!} \right) + C
Why the integral can't be done with integration by parts?
i mean, this far i just know few methods to solve integrals, that is substituting, integration by parts, and with trig subs...
It's because there's no elementary function, whose derivative is sin(x) / x.
One can also define a Sine Integral to be:
\mbox{Si} (x) = \int \limits_{0} ^ x \frac{\sin t}{t} dt
Muzza said:
Nonsense...
Nah, I've so far heard of partial fraction, partial derivative, but not partial integration. It's just ill-worded, and not formal. Yes, one can choose to say partial integration, or integrate by parts, it happens that both are okay. But I myself prefer integrate by parts. And hopefully, most professors and/or mathematicians agree with me!
By the way, is guiding a guy to word formally worth being called nonsense?
 
Last edited:
Nah, I've so far heard of partial fraction, partial derivative, but not partial integration.

A phrase can be in use even if you've never heard of it. Mathworld recognizes it as a synonym of "integration by parts", for example.

It's just ill-worded, and not formal.

You've got to be kidding me...
 

Similar threads

Replies
7
Views
2K
Replies
2
Views
2K
  • · Replies 27 ·
Replies
27
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
3
Views
2K
Replies
3
Views
2K
Replies
14
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
8
Views
1K