Easy integration by parts question.

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Homework Help Overview

The discussion revolves around the integration by parts technique, specifically focusing on the integration of the function xe^yx with respect to x. The original poster expresses uncertainty about the differentiation and integration steps involved in the process.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to clarify the differentiation of u and the integration of dv in the context of integration by parts. They question whether to differentiate u with respect to x and how to properly express dv.

Discussion Status

Some participants confirm the original poster's understanding of differentiating u with respect to x and provide clarification on the expression for dv. There is an exchange of ideas regarding the correct setup for the integration by parts process.

Contextual Notes

Participants are discussing the integration by parts method under the constraints of a homework assignment, which may impose specific requirements or formats for the solution.

Kuma
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Homework Statement



Hi

This is something i don't remember what I'm supposed to do. So anyway here goes.

For example if my function was

xe^yx and i wanted to integrate with respect to dx

then i do an integration by parts with these variables:

u = x dv = e^yx

now my question is, when i try to find du do i differentiate with respect to x? same goes for dv, do i integrate with respect to dx?

suppose instead i chose
u = e^yx and dv = x

then du would be ye^yx?

Hopefully that was clear enough.
 
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Kuma said:
u = x
dv = e^yx

when i try to find du do i differentiate with respect to x?

Yes.

same goes for dv, do i integrate with respect to dx?

Technically, your "dv" expression should be:

dv = eyxdx

...so there's not much to be confused about on that part, at least.
 
ok thanks
 
remember you need

u du v dv

you know u=x dv=e

du=dx v=(1/y)eyx
 

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