Given this joint PDF of X and Y:(adsbygoogle = window.adsbygoogle || []).push({});

So:Code (Text):

X\Y 1 2

0 0.1 0.3

1 0.05 0.1

2 0.2 0.25

P(X = 1| X+Y=2) = 1/2?

P(X <= 1 and Y <= 2) = 1/3?

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# Homework Help: Easy Joint PDF Question

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