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the question is show that (1+i)^(95) =(1-i)*2^(47)
we are told that z^(n) = r^(n) * e^(i*n*theta)
when i do the problem i get
(1+i)^(95) =(1+i)*2^(47)
can anybody verify whether i am right or wrong. thanks
we are told that z^(n) = r^(n) * e^(i*n*theta)
when i do the problem i get
(1+i)^(95) =(1+i)*2^(47)
can anybody verify whether i am right or wrong. thanks
