- #1

Ariastity

- 3

- 0

_{int}

to the output voltage V

_{out}?

## Homework Equations

## The Attempt at a Solution

To calculate the contribution of E

_{int}, I removed the other two voltage sources.

Then, I divided them into three potential dividers, giving me:

V

_{body}= (Z

_{C2}/Z

_{C2}+Z

_{C1}) x E

_{int};

V

_{1}=(Z

_{in1}/Z

_{B1}+Z

_{in1}) x V

_{body};

and V

_{2}=(Z

_{in2}/Z

_{B2}+Z

_{in2 })x V

_{body}

Lastly, Vout= Vbody- V1-V2.

Is this method valid?