EE: Mutual Inductances in Magnetic Circuit

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SUMMARY

The discussion centers on calculating mutual inductances in a symmetric magnetic circuit with three windings, specifically focusing on windings A and B, each having N turns. The participant struggled with deriving the mutual inductances, initially calculating self-inductances but facing challenges with flux linkages and reluctances. Key equations referenced include the relationship between magnetomotive force (mmf), reluctance (R), and flux (ψ). Ultimately, the participant achieved a breakthrough in solving the problem after multiple attempts.

PREREQUISITES
  • Understanding of mutual inductance theory and its symmetry properties
  • Familiarity with magnetomotive force (mmf) and reluctance (R)
  • Knowledge of magnetic flux (ψ) and its relationship to current (i)
  • Basic principles of inductance and magnetic circuits
NEXT STEPS
  • Study the derivation of mutual inductance formulas in magnetic circuits
  • Learn about the application of magnetomotive force (mmf) in circuit analysis
  • Explore the concept of reluctance in magnetic materials and its calculations
  • Investigate examples of complex magnetic circuits with multiple windings
USEFUL FOR

Electrical engineering students, educators, and professionals working with magnetic circuits, inductive components, and electromagnetic theory will benefit from this discussion.

ckpage86
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Homework Statement



The symmetric magnetic circuit has three windings. Winding A and B each have N turns and are wound on the two bottom legs of the core. The core dimensions are indicated in the figure.

b.) Find the mutual inductances between the three pairs of windings.

figure : http://i844.photobucket.com/albums/ab2/cpage86/133ece321hmwk1_zps0b1b4f42.png


Homework Equations



\varphi = \Im/\Re

Inductance = \lambda/current

\lambda = N\varphi


The Attempt at a Solution



In the problem I went through and found the self-inductances for part a.), but cannot get the mutual inductances. I have tried about 15 times, and according to the solution I am close, but still not 100% correct.

I have tried finding the flux in each leg and determining the flux linkages of the coils, but I keep ending up with a huge mess of papers with never-ending equations.

I have tried just utilizing the flux through the gap.

I have tried to blindly guess which reluctances are necessary to solve this.

This class just started this week, and I have read the book. I have gone back and forth through the chapter and the only example that is close to this one is of a square loop core with a single gap and two windings. In that particular example they disregarded the core permeability and completed the necessary work in a few steps; which is pretty misleading not helpful.

Part of my work is here:

http://i844.photobucket.com/albums/ab2/cpage86/fe163d3b-b6a3-420f-b12c-ccc26c537ff5_zps8ee39d5d.jpg

According to the book I am pretty close, but the "la" term in the numerator is not supposed to be there. Other than that, my solution is right on.

I mainly am hoping to gain some insights on how to go about setting this up and solving for the mutual inductances. If you have any advice or wisdom to drop on me I am all ears.
 
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Sorry, can't read your work so I'll start from scratch. Sorry if much or all of this is redundant:

First, do you see that there are only two mutual inductances to be computed? I mean, there are 6 (M1a, Ma1, M2a, Ma2, M12, M21) but 4 are redundant by symmetry and mutual inductance theory.

So let us choose to compute M1a and M12:

Are you familiar with magnetomotive force (mmf) and reluctance R in addition to the usual H, B, flux ψ and current i? What equation relates mmf to reluctance R and flux ψ? where ψ = BA, A = cross-sectional area.

Then, what is the definition of mutual inductance between coil a and coil 1, assuming coil a is excited by a current ia?

The method is to equate mmf to the sum of magnetic potential drops (mpd) around the closed magnetic path.
 
Rude man, Thanks for the reply, I've got some good news. While dining at Arby's yesterday on my lunch break I had a breakthrough and finally solved that bad boy.

The feeling of relief was huge.

:)
 
ckpage86 said:
Rude man, Thanks for the reply, I've got some good news. While dining at Arby's yesterday on my lunch break I had a breakthrough and finally solved that bad boy.

The feeling of relief was huge.

:)

Good going!
 

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