Effect of Change of Potential difference applied to an X-Ray tube

Click For Summary
SUMMARY

Increasing the potential difference applied to an X-ray tube results in a decrease in the minimum wavelength of emitted radiation, as described by the Duane-Hunt law (λ=hc/eV). The discussion also raises the question of how the intensity of emitted radiation is affected by this change in potential difference. While the minimum wavelength decreases, the effect on intensity remains uncertain and requires further exploration.

PREREQUISITES
  • Understanding of X-ray physics, specifically continuous X-rays and cutoff wavelengths.
  • Familiarity with the Duane-Hunt law (λ=hc/eV).
  • Basic knowledge of quantum physics principles.
  • Awareness of X-ray safety protocols in laboratory settings.
NEXT STEPS
  • Research the relationship between potential difference and intensity in X-ray tubes.
  • Study the effects of varying potential differences on X-ray emission spectra.
  • Explore the implications of X-ray intensity in practical applications.
  • Learn about X-ray safety measures and best practices in laboratory environments.
USEFUL FOR

High school students studying physics, educators teaching quantum physics concepts, and anyone interested in the principles of X-ray technology and safety.

Bloopy
Messages
13
Reaction score
1
I am a high school student, so I know only the basics of X-Rays.I simply know about continuous X-rays, cutoff wavelength and threshold wavelength. Now if I increase the potential applied to the X-ray tube, I am certain that the minimum wavelength of emitted radiation decreases. (I say this using λ=hc/eV, which is the Duane-Hunt law)

I am unsure about the intensity of emitted radiation. Does that change?
 
Last edited:
Physics news on Phys.org
Bloopy said:
I am a high school student, so I know only the basics of X-Rays.I simply know about continuous X-rays, cutoff wavelength and threshold wavelength. Now if I increase the potential applied to the X-ray tube, I am certain that the minimum wavelength of emitted radiation decreases. (I say this using λ=hc/eV, which is the Duane-Hunt law)

I am unsure about the intensity of emitted radiation. Does that change?
Is this a general question, or are you working with X-rays in the lab? X-ray safety is an important consideration when working with lab setups.
 
berkeman said:
Is this a general question, or are you working with X-rays in the lab? X-ray safety is an important consideration when working with lab setups.
As I said, I am in high school. There is no practical use of X-Rays. It is just the theoretical part. Actually, my textbook had a multiple choice question saying

"If we increase potential difference applied to an X-Ray tube, what of the following things will happen with the emitted radiation?
A. Intensity increases
B. Intensity decreases
C. Wavelength increases
D. Wavelength decreases.

Now, as I mentioned in the Original Post itself, I used the Duane-Hunt Law to mark the answer as D, which is obviously correct. Out of curiosity I wanted to know what would happen with the intensity. Since I myself did not have much knowledge regarding the issue, I decided not to put it under the homework section and just as a general question of Quantum Physics.
 
Bloopy said:
I decided not to put it under the homework section and just as a general question of Quantum Physics.
Do you have two threads about this? If so, I can merge them into one thread in the schoolwork forums. We do not allow cross-posting here, and we do not allow schoolwork posts ourtide of the schoolwork forums. Thanks.
 
berkeman said:
Do you have two threads about this? If so, I can merge them into one thread in the schoolwork forums. We do not allow cross-posting here, and we do not allow schoolwork posts ourtide of the schoolwork forums. Thanks.
No, I didn't create two threads. Just this one.
 

Similar threads

Replies
11
Views
2K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
11
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 17 ·
Replies
17
Views
4K
Replies
13
Views
3K