Effective Refractive Index - Should be simple

  • Context: Undergrad 
  • Thread starter Thread starter nathangrand
  • Start date Start date
  • Tags Tags
    Index Refractive index
Click For Summary
SUMMARY

The discussion focuses on calculating the effective refractive index (N) for a dielectric composed of alternating layers with widths A and B and refractive indices a* and b*. The incorrect approach initially taken involved calculating time based on distance and speed, leading to an erroneous value for N. The correct formula for the effective refractive index is established as N² = [A(a*)² + B(b*)²] / (A + B). The need to incorporate optical path length into the calculations is emphasized as a crucial factor for accuracy.

PREREQUISITES
  • Understanding of refractive index concepts
  • Familiarity with wave propagation and phase speed
  • Knowledge of optical path length calculations
  • Basic mathematical skills for manipulating equations
NEXT STEPS
  • Study the derivation of effective refractive index in multilayer dielectrics
  • Learn about optical path length and its significance in wave optics
  • Explore applications of effective refractive index in photonic devices
  • Investigate the impact of layer thickness on refractive index calculations
USEFUL FOR

Students and professionals in optics, materials science, and photonics who are involved in designing and analyzing multilayer dielectric structures.

nathangrand
Messages
38
Reaction score
0
Imagine a dielectric made of of alternating layers of widths A and B and refractive indices (a*) and (b*). Find the effective refractive index, N

So in general: c/n = wavelength x frequency = phase speed

My thinking was find the total time taken for the wave to propagate through the distance A+B and work out the refractive index from this.

So,

Time=distance/speed = (A+B)/(c/N) = (A/(c/a*)) +(B/(c/b*))

But this gives me the wrong value for N

The answer I'm looking for is N^2= [A(a*)^2 + B(b*)^2]/(A+B)

Where am I going wrong?
 
Science news on Phys.org
Is it that I need to use the optical path length..ie refractive index x physical length in my calculations? That will make it work I think but can someone explain why...
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
12
Views
2K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 11 ·
Replies
11
Views
1K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K