Effective Refractive Index - Should be simple

AI Thread Summary
The discussion focuses on calculating the effective refractive index (N) for a dielectric composed of alternating layers with different widths and refractive indices. The initial approach involved calculating the total time for a wave to propagate through the layers, but this method yielded an incorrect value for N. The correct formula for N is derived as N^2 = [A(a*)^2 + B(b*)^2]/(A+B). The confusion arises from not incorporating the optical path length, which accounts for the refractive index multiplied by the physical length of each layer. Understanding this concept is crucial for accurately determining the effective refractive index in layered dielectrics.
nathangrand
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Imagine a dielectric made of of alternating layers of widths A and B and refractive indices (a*) and (b*). Find the effective refractive index, N

So in general: c/n = wavelength x frequency = phase speed

My thinking was find the total time taken for the wave to propagate through the distance A+B and work out the refractive index from this.

So,

Time=distance/speed = (A+B)/(c/N) = (A/(c/a*)) +(B/(c/b*))

But this gives me the wrong value for N

The answer I'm looking for is N^2= [A(a*)^2 + B(b*)^2]/(A+B)

Where am I going wrong?
 
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Is it that I need to use the optical path length..ie refractive index x physical length in my calculations? That will make it work I think but can someone explain why...
 
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