Calculating Efficiency of a Heat Engine: Converting Celsius to Kelvin

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To calculate the efficiency of a heat engine, temperatures must be converted from Celsius to Kelvin using the formula eff = [1 - (T cold/T hot)] * 100. An example calculation shows that for T cold at 302°C (incorrectly noted as 593K, should be 575K) and T hot at 610°C (883K), the efficiency is approximately 32.8%. It's important to note that this formula represents the efficiency of an ideal heat engine, while real engines will have lower efficiency. The discussion highlights the necessity of accurate temperature conversion for proper efficiency calculations. Overall, precision in temperature values is crucial for determining heat engine efficiency.
cowgiljl
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when i am calculating the eggiciency of a heat engine i have to convert the celicus to kelvis and used this formula

eff = 1-(T cold/T hot)*100

fro example 302C = 593K 610C = 883K

eff = 1-593/883 = about 32.8% efficient

right ?

thanks joe
 
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Originally posted by cowgiljl
eff = 1-(T cold/T hot)*100
You mean: eff = [1-(T cold/T hot)]*100.

This is the efficiency of an ideal (reversible) heat engine; real engines will be less efficient.
...
eff = 1-593/883 = about 32.8% efficient
Right.
 
Originally posted by cowgiljl
fro example 302C = 593K

Nope, 302+273=575.
 
it was 320 not 302 but thanks
 


Originally posted by Tom
Nope, 302+273=575.
Good catch, Tom. :smile:
 

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