Efficiency of Car Jack - Physics 11 Help

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To determine the efficiency of the car jack, the formula eff = (mgh/f*d) x 100% is used. The car jack exerts a force of 3000N to lift the car 10 cm, while the user applies a force of 1200N over a distance of 30 cm. By substituting the values into the formula, the efficiency can be calculated. The discussion highlights the need for clarity in applying the physics concepts to solve the problem. Ultimately, understanding the relationship between input and output forces is crucial for calculating efficiency.
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Physics 11 help??!

Homework Statement



a car jack applies a force of 3000N to lift one side of a car a distance of 10 cm. in order to accomplish this the person using the jack needed to apply a force of 1200N to the handle moving it 30 cm. what is the jack's efficiency?

Homework Equations



eff = (mgh/f*d) x 100%

The Attempt at a Solution



idk where 2 start??
 
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