Efficient U-Substitution for (x^2)(sinx)/(1+x^6)

nameVoid
Messages
238
Reaction score
0
[ ( x^2 ) ( sinx ) ] / (1 + x^6)
 
Physics news on Phys.org
17.4
 
Cristo, I get 42. You might have forgotten to multiply by Hooker's constant (= 2.413793103).
 
Don't listen to these clowns. The answer you seek is

[ ( u^2 ) ( sinu ) ] / (1 + u^6)
 
jbunniii said:
Don't listen to these clowns. The answer you seek is

[ ( u^2 ) ( sinu ) ] / (1 + u^6)

That's an extremely useful substitution in those cases where you find the given variable esthetically displeasing for some reason.

For all other cases, not so much.
 
nameVoid,
If you're still out there, you would have gotten more serious (and helpful) responses if you had given us the complete problem. We can infer that this is an integration problem, although there was no indication of that in what you wrote. Also, if you want help, show us what you've tried.

The integral looks to me like it could be done using integration by parts in this way:
u = cos x
dv = \frac{x^2 dx}{1 + x^6}

To find v, you'll have to integrate dv, which involves a substitution w = x3, dw = 3x2dx. I haven't worked it out, but this is what I would try first.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top