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Homework Statement
{\frac {65-75\,{e^{-5\,k}}}{1-{e^{-5\,k}}}}={\frac {60-75\,{e^{-10\,k}<br /> }}{1-{e^{-10\,k}}}}
Homework Equations
{e}^{x}=k implies x=\ln \left( k \right), as well as other properties of logarithms.
The Attempt at a Solution
Maple makes short work of this, giving k=1/5\,\ln \left( 2 \right), but I'm totally lost as to how to solve it myself.