Efficiently Calculate Stopping Time for a Cyclist | Displacement Homework

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The discussion focuses on calculating the stopping time for a cyclist who slows from 11.0 m/s to 3.0 m/s after applying brakes. The deceleration was determined to be -3.2 m/s², and the time to reduce speed to 0 m/s was calculated to be approximately 0.9375 seconds. The method used to find the stopping time is confirmed as correct, emphasizing the importance of applying the appropriate kinematic equations. The conversation highlights the need to ensure all variables are accurately accounted for in the calculations. Overall, the approach to solving the problem is validated by peers in the discussion.
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Homework Statement


A cyclist is traveling with a speed of 11.0 m/s when she applies the brakes. After slowing for 2.5s, her speed has been reduced to 3.0 m/s. If she continues braking, how much longer will it take her to stop?

I found the deceleration to be -3.2 m/s^2
V1 = 3.0 m/s
V2 = 0

2. The attempt at a solution

I used the equation V2 = V1 + (a)(t) and got the change in time to be 0.9375s

Does this seem like the correct way to solve this?
 
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Well you found her deceleration correctly, so now what you want to get is the time it takes the cyclist to go from 11 m/s to 0 m/s.
 
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