Since the LHS is a function of time as well as position while the LHS is position only, not really. However ... let's say we have a set of wavefunctions [itex]\{ \psi_n \}[/itex] which has been selected so that [tex]\mathbf{H}\psi_n = E_n\psi_n[/tex] ... then each [itex]\psi_n[/itex] is said to be an eigenfunction of the Hamiltonian with eigenvalue [itex]E_n[/itex].
A system prepared in a superpostion state may have wavefunction [tex]\psi = \frac{1}{\sqrt{2}}\left ( \psi_1 + \psi_2\right )[/tex] (assuming each [itex]\psi_n[/itex] are already normalized.) In this case [itex]\psi[/itex] is not an eigenfunction of the Hamiltonian.
In general, the set of eigenfunctions of an operator can be used as a basis set. Any wavefunction can. Therefore, be represented in terms of a superposition of eigenfunctions ... including eigenfunctions of another operator. (Just in case someone infers that superpositions of eigenfunctions cannot be eigenfunctions.) It is also possible for a wavefunction to, simultaniously, be an eigenfunction of more than one operator.
Notice how careful I was in the way I phrased things above?
In QM it is very important to be careful about what exactly is being said about a system ... when you are starting out it is as well to get really pedantic about this.