Eigenfunctions of an Integral Operator

[Kreizhn]

Homework Statement

If there are any eigenvalues for the following integral operator, calculate them

Kf(t) = \int_0^1 (1+st) f(s) \ ds

The Attempt at a Solution

I've tried making this into a differential equation, to no avail. I've also just tried solving the equation Kf(t) = \lambda f(t) though that also didn't lead anywhere. I'm not sure if there's some special way of attacking problem like this. Does anybody have any ideas?

 

[Dick]

It's a lot easier than you are think it is. Your integral expression is a linear function of t, no matter what f is.

 

[lanedance]

not too sure.. but how about noticing the t depndence of the function... does the fact
\int_0^1 f(s) ds
and
\int_0^1 sf(s) ds
are constants help..

 

[Kreizhn]

I had tried looking for eigenfunctions of the form a + bt but for some reason got an inconsistent system of equations. I'll go back and look at it again.

 

[lanedance]

i haven't tried, but for non-zero b
(a+bt) = b(a/b+t)

so if (a+bt) is an eigenfunction, then so is (a/b+t) = c+t which ma be easier to deal with

 

[Kreizhn]

So if try a function of the form f(t) = t + a and try K f(t) = \lambda f(t) I get the following system of equations
\begin{align*}<br /> \frac13 + \frac a2 &amp;= \lambda \\<br /> \frac12 + a &amp;= \lambda a<br /> \end{align*}<br />

I can solve this to get a = 1.868517092, \lambda = 1.267591879. But it seems odd that an integral operator would only have one eigenvalue in it's spectrum. Furthermore, how can I be sure that this is exhaustive? How would I find other eigenvalues and eigenfunctions?

 

[lanedance]

the only other option is a constant, which i don't think works as you end up with a t dependence

 

[Kreizhn]

Indeed, so you're saying that the only possible eigenfunctions are of the form f(t) = t+a since for all other functions, Kf(t) will be first order polynomial in t.

 

[Dick]

So if try a function of the form f(t) = t + a and try K f(t) = \lambda f(t) I get the following system of equations
\begin{align*}<br /> \frac13 + \frac a2 &amp;= \lambda \\<br /> \frac12 + a &amp;= \lambda a<br /> \end{align*}<br />

I can solve this to get a = 1.868517092, \lambda = 1.267591879. But it seems odd that an integral operator would only have one eigenvalue in it's spectrum. Furthermore, how can I be sure that this is exhaustive? How would I find other eigenvalues and eigenfunctions?

Don't you get a quadratic equation in lambda? Aren't there two eigenvalues?

 

[Kreizhn]

Yes. I was being lazy an had plugged this into a Maple to solve numerically. But it isn't hard to do algebraically. I realized this, but figured the thread was dead so it wasn't important to post it :P

 

[Dick]

Yes. I was being lazy an had plugged this into a Maple to solve numerically. But it isn't hard to do algebraically. I realized this, but figured the thread was dead so it wasn't important to post it :P

Sure. Just checking...