mmpstudent
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I can do this derivation the old fashioned way, but am having trouble doing it with einstein summation notation.
Since \vec{B}=\nabla \times \vec{a}
\vec{B}=\mu_{0}/4\pi (\nabla \times (m \times r)r^{-3}))
4\pi \vec{B}/\mu_{0}=\epsilon_{ijk} \nabla_{j}(\epsilon_{klm} m_{l} r_{m} r^{-3})
=(\delta_{il}\delta_{jm}-\delta_{im}\delta_{jl})\partial_{j}m_{l}r_{m}r^{-3}
here is where I am stumbling. My professor has for the next step
=m_{l}(\delta_{il}\delta_{jm}-\delta_{im}\delta_{jl})r^{-3} \delta_{jm}-3 r_{m}\hat{r}_{j}r^{-4})
but I don't really know how to get to that step
Since \vec{B}=\nabla \times \vec{a}
\vec{B}=\mu_{0}/4\pi (\nabla \times (m \times r)r^{-3}))
4\pi \vec{B}/\mu_{0}=\epsilon_{ijk} \nabla_{j}(\epsilon_{klm} m_{l} r_{m} r^{-3})
=(\delta_{il}\delta_{jm}-\delta_{im}\delta_{jl})\partial_{j}m_{l}r_{m}r^{-3}
here is where I am stumbling. My professor has for the next step
=m_{l}(\delta_{il}\delta_{jm}-\delta_{im}\delta_{jl})r^{-3} \delta_{jm}-3 r_{m}\hat{r}_{j}r^{-4})
but I don't really know how to get to that step
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