Einstein summation notation for magnetic dipole field

AI Thread Summary
The discussion focuses on deriving the magnetic dipole field using Einstein summation notation, with a participant expressing difficulty in progressing through the derivation. They reference the relationship between the magnetic field and vector potential, highlighting a specific step where they encounter confusion. Another participant critiques the professor's application of Einstein notation, suggesting that it misrepresents the notation's purpose. They provide a clearer formulation of the equations involved, emphasizing the use of the product rule for derivatives. The conversation concludes with a request for additional resources to practice Einstein summation notation further.
mmpstudent
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I can do this derivation the old fashioned way, but am having trouble doing it with einstein summation notation.

Since \vec{B}=\nabla \times \vec{a}
\vec{B}=\mu_{0}/4\pi (\nabla \times (m \times r)r^{-3}))
4\pi \vec{B}/\mu_{0}=\epsilon_{ijk} \nabla_{j}(\epsilon_{klm} m_{l} r_{m} r^{-3})
=(\delta_{il}\delta_{jm}-\delta_{im}\delta_{jl})\partial_{j}m_{l}r_{m}r^{-3}

here is where I am stumbling. My professor has for the next step

=m_{l}(\delta_{il}\delta_{jm}-\delta_{im}\delta_{jl})r^{-3} \delta_{jm}-3 r_{m}\hat{r}_{j}r^{-4})

but I don't really know how to get to that step
 
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You may be interested in the The LaTeX guide for the forum. :smile: Link.
 
Fredrik said:
You may be interested in the The LaTeX guide for the forum. :smile: Link.

You were too fast. Was trying to get it to work just needed to delete the spaces in brackets I guess.
 
My first thought is that he's using the product rule for derivatives to evaluate ##\partial_j## acting on a product.
 
First off, tell your professor that he is horribly butchering Einstein notation. Seriously, what was written down misses the entire point of the notation. Anyways, ##\frac{4\pi}{\mu_{0}}B^{i} = \frac{4\pi}{\mu_{0}}\epsilon^{ijk}\partial_{j}A_{k} = \epsilon^{ijk}\epsilon_{klm}m^{l}[r^{-3}\partial_{j}r^{m} + r^{m}\partial_{j}(r^{-3})]## hence ##\frac{4\pi}{\mu_{0}}\epsilon^{ijk}\partial_{j}A_{k} = 2\delta^{[i}_{l}\delta^{j]}_{m}m^{l}[r^{-3}\partial_{j}r^{m} + r^{m}\partial_{j}(r^{-3})]##. Now, ##\partial_{j}r^{m} = \delta^{m}_{j}## and ##\partial_{j}(r^{-3}) = -3(-r^i r_{i})^{-5/2}r_{k}\partial_{j}r^{k} = -3r^{-4}\hat{r}_{j}## giving us ##\frac{4\pi}{\mu_{0}}\epsilon^{ijk}\partial_{j}A_{k} = 2\delta^{[i}_{l}\delta^{j]}_{m}m^{l}[r^{-3}\delta^{m}_{j} -3r^{-4}\hat{r}_{j}r^{m}]## as desired.

EDIT: By the way, in the above it should be ##(r^i r_{i})^{-5/2}## not ##(-r^i r_{i})^{-5/2}##; I've gotten too used to General Relativity xD.
 
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O wow, thanks. that makes much more sense now.
 
Do you know of any materials online that would give more written out examples of such derivations with Einstein summation? I just need more practice
 
mmpstudent said:
Do you know of any materials online that would give more written out examples of such derivations with Einstein summation? I just need more practice
I honestly can't think of any online resources off of the top of my head because I got used to the notation when learning special relativity (the text used was Schutz).
 
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