Elastic Collision of a 90kg ball

AI Thread Summary
In the discussion about the elastic collision of a 90g ball with a stationary 10g ball, the initial momentum is calculated as 9000 g.cm/s for the moving ball. For part (a), when the balls stick together, the final speed is determined to be 90 cm/s. However, for part (b), which involves a perfectly elastic collision, the velocities after impact differ, and the correct approach requires using both conservation of momentum and conservation of energy equations. The key point is that the relative velocity before and after the collision remains constant in elastic collisions. Understanding these principles is essential to solve for the new velocities of both balls.
Lyphta
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Homework Statement


A 90-g ball moving at 100 cm/s collides head-on with a stationary 10-g ball. Determine the speed of each after impact if (a) they stick together, (b) the collision is perfectly elastic.

Homework Equations


p=mv

The Attempt at a Solution


I already solved A, but I don't know how to do B. So far, I've gotten:

p=mv
= 90(100)
= 9000 g.cm/s

p=mv
= 10 (0)
= 0

so...
p1+p2=p3
m1 v1 + m2 v2 = (m1 +m2)v
90(100) + 0 = 100v
v= 90 cm/s

I don't understand how the answer can be 80 cm/s when they perfectly elastic. Shouldn't it be 90 cm/s?
 
Last edited:
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p1+p2=p3
m1 v1 + m2 v2 = (m1 +m2)v
90(100) + 0 = 100v
v= 90 cm/s

This answer is for (a). In the part (b) after impact both bodies will have different velocities. So wrigth down two equations. One for coservation of linear momentum and another for conservation of energy. Then solve for the new velocities of the two bodies.
 
Lyphta said:

The Attempt at a Solution


I already solved A, but I don't know how to do B. So far, I've gotten:

One method has already been given. You can also use the fact that the relative velocity before collision is equal to the relative velocity after collision, because the collision is fully elastic.
 
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