Elastic Collision of Blocks on a Half-Pipe: How to Determine the Final Heights?

AI Thread Summary
Two blocks on a frictionless half-pipe collide elastically after being released from different heights. Block B is more massive and starts from a lower height than Block A. The discussion centers on determining the final heights of the blocks post-collision, with various potential outcomes presented. Participants emphasize the importance of using conservation of momentum and energy to solve the problem, though some express confusion over how to apply these concepts without specific numerical values. A clear understanding of these principles is essential for determining the final heights of the blocks.
fightboy
Messages
25
Reaction score
0
Two blocks are released from rest on either side of a frictionless
half-pipe. Block B is more massive than
block A. The height HB from which block B is released is less
than HA, the height from which block A is released. The blocks
collide elastically on the flat section. After the collision, which
is correct?
A. Block A rises to a height greater than HA and block B
rises to a height less than HB.
B. Block A rises to a height less than HA and block B
rises to a height greater than HB.
C. Block A rises to height HA and block B rises to
height HB.
D. Block A rises to height HB and block B rises to
height HA.
E. The heights to which the blocks rise depends on where
along the flat section they collide.
I honestly didn't understand where to start with this problem, and got confused on the solution walkthrough. It basically wrote out two equations based on the conservation of momentum and conservation of energy, which said could be used to calculate the final speeds and then the final heights. Is there a more intuitive, less complicated way of figuring out this problem or does it require multiple equations? If someone could kindly give me an explanation for this problem it would be much appreciated!
 
Physics news on Phys.org
Well we can't really give you an explanation, that would be doing your homework for you. Conservation of energy and momentum are good places to start, do you know why?
 
BiGyElLoWhAt said:
Well we can't really give you an explanation, that would be doing your homework for you. Conservation of energy and momentum are good places to start, do you know why?
Well since it's an elastic collision I know Kf=Ki and due to the conservation of momentum Pf=Pi but i don't know how to put these two equations together to determine which height each of the blocks rises too. I can't really understand how the book uses the equations since the explanation is very vague. I guess I'm more confused since they don't give number values in this problem.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top