(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

a moving train collides with a train that is not moving, and the trains use their springy bumpers to bounce off of each other without damage. Assume diff masses for train A and B. Identify your isolated system, solve for the final velocity of EACH train in terms of INITIAL VELOCITY of the initially moving train and the 2 masses

2. Relevant equations

P=mv

Conservation of momentum: Pfinal=Pinitial

Assumption of no external forces, spring as part of the system. k not addressed

3. The attempt at a solution

pi=[mA](v_{i}A) (since B is at rest)

pf=[mA](v_{f}A)+[mB](v_{f}B)

pi=pf

[mA](v_{i}A)=[mA](v_{f}A)+[mB](v_{f}B)

since A's final velocity defined as in the negative direction in my system

[mA](v_{i}A)=-[mA](v_{f}A)+[mB]()

v_{f}A = [[mB]v_{f}B-[mA](v_{i}A)]/mA

v_{f}B = [[mA]v_{f}A+[mA](v_{i}A)]/mB

my questionthis is the furthest i got to. I do not know if i am right or wrong. But it seems like thats not the furtherst i can solve this problem. since the final velocity variable still are present in both

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# Homework Help: Elastic collision with conservation of energy and momentum?

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