Elastic collisions and steel ball

AZONIn summary, a 56g steel ball is dropped from rest and strikes a steel plate, with a contact time of .5ms. The ball then rebounds elastically and returns to its original height. The time interval for a round trip is 8.00s. To find the average force exerted on the ball during contact with the plate, we must use the formula for impulse, which is the change in momentum divided by the time interval. By finding the momentum of the ball just before it hits the surface and just after the collision, and then dividing by the time interval of the collision, we can determine the average force. This can be found by finding the height the ball was dropped from, its velocity just before and
  • #1
williams31
38
0
A 56g steel ball is released from rest and falls vertically onto a steel plate. The ball strikes the plate and is in contact with it for .5ms. The ball rebounds elastically, and returns to its original height. The time interval for a round trip is 8.00s. In this situation, the average force exerted on the ball during contact with the plate is closest to:
A) 4390 N
B) 10,260 N
C) 5870 N
D) 7300 N
E) 8780 N

I was wondering what formula I should use to solve the problem.
 
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  • #2
This is an impulse question right here. The formulas for impulse are your best friend in this case. Remember that it's not exactly straitfoward, but requires a little though outside of the definition of Impulse. Hope that gets you started.
 
  • #3
Im not sure if I am following you.
 
  • #4
williams31 said:
A 56g steel ball is released from rest and falls vertically onto a steel plate. The ball strikes the plate and is in contact with it for .5ms. The ball rebounds elastically, and returns to its original height. The time interval for a round trip is 8.00s. In this situation, the average force exerted on the ball during contact with the plate is closest to:
A) 4390 N
B) 10,260 N
C) 5870 N
D) 7300 N
E) 8780 N

I was wondering what formula I should use to solve the problem.
the average force during a collision is the change of momentum divided by the time interval during which the force acts. Here, by change of momentum, I mean the final momentum (after the collision) minu sthe initial momentum (before the collision). You have to be careful, this is a vector difference!
 
  • #5
Im lost...but thanks for your guys help anyway.
 
  • #6
williams31 said:
Im lost...but thanks for your guys help anyway.
First step: find the momentum of the ball *just* before it hits the surface (you may essentially treat its height as being zero). You know it takes 4 seconds to fall and it started from rest so you may find the velocity it has once it reaches the surface. The magnitude of the momentum will be the mass times the speed. (here, I am treating the time that the collision last negligible compared to the time of fall)

Second step: If the collision is elastic, what is the momentum just after the collision? If you take the momentum vector just after minus the momentum vector just before the collision, you get a difference which is not zero. What is its magnitude?

Third step: take this last result and divide by the time interval of the collision.
 
  • #7
williams31 said:
Im lost...but thanks for your guys help anyway.
What is the height that the ball is dropped from? (You can work this out from the time of the round trip).
What is its velocity just before it strikes the plate?
What is it after?
What is the change in velocity?
What is the change in momentum?
What is the relationship between (average) Force, time, and change in momentum?

Answer those questions and you will have your answer.

AM
 

1. What is an elastic collision?

An elastic collision is a type of collision in which the total kinetic energy of the system is conserved. This means that the energy before the collision is equal to the energy after the collision.

2. How does a steel ball behave in an elastic collision?

In an elastic collision, a steel ball will retain its shape and size after colliding with another object. It will also transfer its kinetic energy to the other object, causing it to move with the same velocity as the steel ball before the collision.

3. What factors affect the elasticity of a collision?

The elasticity of a collision is affected by the materials involved and their physical properties, such as their composition, density, and stiffness. The speed and angle of impact also play a role in determining the elasticity of a collision.

4. How is the coefficient of restitution related to elastic collisions?

The coefficient of restitution is a measure of the elasticity of a collision. It is defined as the ratio of the relative velocity of separation to the relative velocity of approach between two objects. In an elastic collision, the coefficient of restitution will be equal to 1.

5. What real-life applications involve elastic collisions with steel balls?

Elastic collisions with steel balls are commonly observed in sports such as billiards, where the balls retain their shape and energy after colliding with each other. They are also used in engineering and physics experiments to study the principles of motion and energy conservation.

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