Electric current and forces problem

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SUMMARY

The problem involves calculating the force on one of three parallel wires arranged in an equilateral triangle, each carrying a current of 50A. The formula used is F = (2*10^-7)(50)(50)/d, where d is the distance between the wires. In this case, the distance d is 10cm, as each side of the triangle measures 10cm. The discussion clarifies that the wires can be considered parallel despite their triangular arrangement due to their orientation in the same direction.

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steve12
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Hi,im trying to work out this problem but i am slightly confused by the way in which it is phrased.It states:

Three parallel wires,arranged in the form of an equilateral triangle, of side length 10cm,each carry a current of 50A in the same direction.Calculate the force on anyone wire due to the other two.


I am going to use: F = (2*10^-7)(50)(50)/d

however i don't know what value to enter for the distance d between them.i also don't understand how the three wires can be parallel yet arranged in the form of an equilateral triangle??do i just resolve the components of one wire into parallel and perpendicular to the 2nd wire and use the parallel value in my calculations maybe?

any help or guidance would be much appreciated
thanks steve:smile:
 
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The wires (#) are arranged like so;

...#


#...#

(ignore the dots) going into and out of the screen; therefore d = 10cm in each case. Please post your homework questions in the homework forums in future, thanks :smile:
 
oh i see,thanks a mill for that!and sorry-will do in future!
cheers
steve
 

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