Electric Current as a function of time

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Homework Help Overview

The problem involves calculating the total charge passing through a conductor over a specified time interval, given an electric current that varies with time according to a sinusoidal function.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of definite integrals to find the total charge from the current function. There is uncertainty regarding the results obtained from the integral, particularly whether the limits yield a non-zero value.

Discussion Status

The discussion is ongoing, with participants exploring the implications of using different settings on calculators and questioning the results of the integral. There is a focus on clarifying the evaluation of the integral at specific limits.

Contextual Notes

Participants mention potential issues with calculator settings, specifically between radians and degrees, which may affect the results of the calculations. The time interval for the charge calculation is also noted as being limited to a quarter of a cycle of the sinusoidal function.

jmuduke
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Homework Statement


8. An electric current in a conductor varies with time according to the expression
I(t) = 100 sin (120*pi*t), where I is in amperes and t is in seconds. What is the total charge passing a given point in the conductor from t = 0 to t = 1/240 s?




Homework Equations






The Attempt at a Solution


I have attempted to substitute the values of t into the equation and use the difference, but I do not feel that was the correct way. Next, I attempted to perform a definite integral, but I get 0 for both numbers.
 
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welcome to pf!

hi jmuduke! welcome to pf! :smile:
jmuduke said:
I(t) = 100 sin (120*pi*t), where I is in amperes and t is in seconds. What is the total charge passing a given point in the conductor from t = 0 to t = 1/240 s?

I attempted to perform a definite integral, but I get 0 for both numbers.

yes, I = dQ/dt, so Q = ∫ I dt

it's only over 90°, so you shouldn't get 0 for both limits :confused:

show us what you did :smile:
 
Thanks for the reply Tim!

I calculated the integral and got -(5 cos(120*pi*t))/6*pi

Originally, my calculator was set in radians, so that could have been why I got 0 for both limits. I changed it to degrees and got -0.265 for both limits then, but that result in the definite integral being 0, correct?
 
hi jmuduke! :smile:

(just got up :zzz:)
jmuduke said:
I calculated the integral and got -(5 cos(120*pi*t))/6*pi

… got -0.265 for both limits then, but that result in the definite integral being 0, correct?

yes, cos(0) = 1, so that's correct for the t = 0 limit :smile:

but for t = 1/240, cos(120πt) = cos(π/2) = cos90° = 0 :wink:
 

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