Electric Current as a function of time

AI Thread Summary
The discussion revolves around calculating the total charge passing a point in a conductor where the electric current varies with time as I(t) = 100 sin(120πt). The user initially attempted to find the charge using substitution and a definite integral but encountered issues, receiving a result of zero. It was clarified that the integral should be calculated correctly over the specified time interval, and the user realized their calculator was initially set to the wrong mode. After correcting this, they calculated the integral but still questioned the outcome, leading to a discussion on the evaluation of cosine at specific limits. The conversation emphasizes the importance of proper integration techniques and understanding trigonometric evaluations in the context of electric current.
jmuduke
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Homework Statement


8. An electric current in a conductor varies with time according to the expression
I(t) = 100 sin (120*pi*t), where I is in amperes and t is in seconds. What is the total charge passing a given point in the conductor from t = 0 to t = 1/240 s?




Homework Equations






The Attempt at a Solution


I have attempted to substitute the values of t into the equation and use the difference, but I do not feel that was the correct way. Next, I attempted to perform a definite integral, but I get 0 for both numbers.
 
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welcome to pf!

hi jmuduke! welcome to pf! :smile:
jmuduke said:
I(t) = 100 sin (120*pi*t), where I is in amperes and t is in seconds. What is the total charge passing a given point in the conductor from t = 0 to t = 1/240 s?

I attempted to perform a definite integral, but I get 0 for both numbers.

yes, I = dQ/dt, so Q = ∫ I dt

it's only over 90°, so you shouldn't get 0 for both limits :confused:

show us what you did :smile:
 
Thanks for the reply Tim!

I calculated the integral and got -(5 cos(120*pi*t))/6*pi

Originally, my calculator was set in radians, so that could have been why I got 0 for both limits. I changed it to degrees and got -0.265 for both limits then, but that result in the definite integral being 0, correct?
 
hi jmuduke! :smile:

(just got up :zzz:)
jmuduke said:
I calculated the integral and got -(5 cos(120*pi*t))/6*pi

… got -0.265 for both limits then, but that result in the definite integral being 0, correct?

yes, cos(0) = 1, so that's correct for the t = 0 limit :smile:

but for t = 1/240, cos(120πt) = cos(π/2) = cos90° = 0 :wink:
 
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