Electric Current of an Orbiting Electron

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SUMMARY

The discussion focuses on calculating the current (I) of an electron orbiting a proton using the Bohr model. The equation I = e² / sqrt(kε₀r³m) is derived, where k is defined as 1/4πε₀. The user equates Coulomb's force law (F = kq₁q₂/r²) with centripetal force (mω²r) to derive ω² = ke²/mr³. The user expresses uncertainty in rearranging the equations to match the required form, particularly in utilizing the relationship I = q/t.

PREREQUISITES
  • Understanding of the Bohr model of the atom
  • Familiarity with Coulomb's force law
  • Knowledge of centripetal force concepts
  • Basic principles of electric current and charge
NEXT STEPS
  • Explore the derivation of the Bohr model equations in detail
  • Study the relationship between angular frequency and current in circular motion
  • Learn about the implications of ε₀ in electromagnetic theory
  • Investigate the application of I = q/t in various physical systems
USEFUL FOR

Students studying atomic physics, educators teaching the Bohr model, and anyone interested in the relationship between electric current and orbital mechanics.

FelaKuti
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Homework Statement


The question is based on the Bohr model with an electron with charge e and mass m orbiting a proton about a circular radius r.

I have to find k in the equation I = e2 / sqrt kε0r3m

where k is a some combination of constants.

Homework Equations



Coulumb's force law: F = kq1q2/r2

Centripetal force: mω2r

Current: I = q/t

k = 1/4πε0

The Attempt at a Solution



I equated columb's force law to the centripetal force to give mω2r = ke2/r2

Then rearranged to get ω2 = ke2/mr3

Then I changed ω for 2π/T and square rooted both sides to give 2π/T = ke2/mr3

From here I'm just not sure how to get it into the form of the equation asked for.
 
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FelaKuti said:
ω2 = ke2/mr3

2π/T = ke2/mr3
The left side of the second equation above has an error (maybe just typographical).

From here I'm just not sure how to get it into the form of the equation asked for.
Try to make use of I = q/t.
 

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