Electric Dipole Moment of copper and sulphate ions

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SUMMARY

The electric dipole moment of a CuSO4 molecule is established at 3.2 x 10^-32 C-m. To determine the separation between the copper ion (Cu²⁺) and the sulfate ion (SO₄²⁻), the formula for electric dipole moment, defined as 2aq, is utilized. The separation is calculated to be 10^-3 m, with 'q' representing the charge of the ions, specifically twice the charge of an electron due to the doubly ionized nature of copper and sulfate.

PREREQUISITES
  • Understanding of electric dipole moment concepts
  • Familiarity with ionization states of copper and sulfate ions
  • Basic knowledge of charge calculations in electrostatics
  • Proficiency in algebraic manipulation of equations
NEXT STEPS
  • Research the properties of electric dipole moments in ionic compounds
  • Study the ionization process of Cu²⁺ and SO₄²⁻ ions
  • Learn about the calculation of electric dipole moments in different molecular structures
  • Explore the implications of dipole moments in chemical bonding and molecular interactions
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Chemistry students, physicists, and researchers interested in molecular interactions and the behavior of ionic compounds in electric fields.

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Homework Statement


The electric dipole moment of a CuSO4 molecule is 3.2 * 10^-32 (i.e. 10 raised to the power of -32)C-m. Find the separation between the copper and sulphate ions.


Homework Equations



Electric deipole moment = 2aq where 2a=separation between the two charges q and -q



The Attempt at a Solution



I am unable to proceed with the given data, because I need to find out the value of q. Please help me with some clues.The answer is 10^-3m. Thanks.
 
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I suggest you Google "Copper Sulfate" and find out how ionized each component is (eg. If the compound is formed by doubly ionized Copper, you would have [itex]\text{Cu}^{2+}[/itex] and [itex]\text{SO}_4{}^{2-}[/itex] and so [itex]q[/itex] would be 2 times the charge of the electron).
 

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