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Electric Dipole Moment of copper and sulphate ions

  1. Feb 17, 2010 #1
    1. The problem statement, all variables and given/known data
    The electric dipole moment of a CuSO4 molecule is 3.2 * 10^-32 (i.e. 10 raised to the power of -32)C-m. Find the separation between the copper and sulphate ions.

    2. Relevant equations

    Electric deipole moment = 2aq where 2a=separation between the two charges q and -q

    3. The attempt at a solution

    I am unable to proceed with the given data, because I need to find out the value of q. Please help me with some clues.The answer is 10^-3m. Thanks.
  2. jcsd
  3. Feb 17, 2010 #2


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    I suggest you Google "Copper Sulfate" and find out how ionized each component is (eg. If the compound is formed by doubly ionized Copper, you would have [itex]\text{Cu}^{2+}[/itex] and [itex]\text{SO}_4{}^{2-}[/itex] and so [itex]q[/itex] would be 2 times the charge of the electron).
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