Electric field and an equilateral triangle

  • Thread starter abeltyukov
  • Start date
  • #1
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Homework Statement



Three 8 cm long rods form an equilateral triangle. Two of the rods are charged to +8 nC, the third to -8 nC. What is the electric field strength at the center of the triangle?


Homework Equations



E = 4piKλL

The Attempt at a Solution



I found the radius of the triangle to be 4.2688 cm. I tried doing E = 4(pi)(9 x 10^9)(100 nC/m) (.042688 m) but that seems wrong. Is L not the radius of the triangle?


Thanks!
 

Answers and Replies

  • #2
312
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Whats the height of the triangle? Divide that by 2
 
  • #3
32
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I still don't get the right answer when I plug in 0.0472 m for L. Any ideas?

Thanks!
 
  • #4
312
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Thats still not it...start by finding the height
 
  • #5
32
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The height is 4.72 cm, right? sqrt (8^2 + 4^2). Where do I go from there?

Thanks!
 
  • #6
312
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This is not resolving vectors if thats what youre thinking. The hypotenuse is 8 cm and one of the sides is 4 cm. Then you need to cut that height in half
 

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