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Electric field and an equilateral triangle

  1. Jan 15, 2007 #1
    1. The problem statement, all variables and given/known data

    Three 8 cm long rods form an equilateral triangle. Two of the rods are charged to +8 nC, the third to -8 nC. What is the electric field strength at the center of the triangle?


    2. Relevant equations

    E = 4piKλL

    3. The attempt at a solution

    I found the radius of the triangle to be 4.2688 cm. I tried doing E = 4(pi)(9 x 10^9)(100 nC/m) (.042688 m) but that seems wrong. Is L not the radius of the triangle?


    Thanks!
     
  2. jcsd
  3. Jan 15, 2007 #2
    Whats the height of the triangle? Divide that by 2
     
  4. Jan 15, 2007 #3
    I still don't get the right answer when I plug in 0.0472 m for L. Any ideas?

    Thanks!
     
  5. Jan 15, 2007 #4
    Thats still not it...start by finding the height
     
  6. Jan 15, 2007 #5
    The height is 4.72 cm, right? sqrt (8^2 + 4^2). Where do I go from there?

    Thanks!
     
  7. Jan 16, 2007 #6
    This is not resolving vectors if thats what youre thinking. The hypotenuse is 8 cm and one of the sides is 4 cm. Then you need to cut that height in half
     
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