Electric field and potential outside and inside nonuniform spherical shell

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SUMMARY

The discussion focuses on calculating the electric field and potential inside and outside a hollow spherical shell with a charge density proportional to the distance from the origin, expressed as ρ = kr. The electric field inside the shell (for r < a) is confirmed to be zero due to no enclosed charge. For the region between the inner radius (a) and outer radius (b), the electric field is derived using Gauss' law, resulting in E = (k(r^4 - a^4)) / (4εr^2). Outside the shell (for r ≥ b), the electric field simplifies to E = (k(b^4 - a^4)) / (4εr^2).

PREREQUISITES
  • Understanding of Gauss' law for electric fields
  • Familiarity with charge density concepts
  • Knowledge of spherical coordinates in electrostatics
  • Basic calculus for integrating charge density over volume
NEXT STEPS
  • Study the derivation of electric fields using Gauss' law in various geometries
  • Explore the implications of nonuniform charge distributions on electric fields
  • Learn about the relationship between electric potential and electric field
  • Investigate the effects of different charge density functions on electric field calculations
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Students and professionals in physics, particularly those studying electromagnetism, as well as educators looking for examples of electric field calculations in nonuniform charge distributions.

krickette
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Homework Statement


Find the electric field and potential inside and outside a hollow spherical shell (a [tex]\leq[/tex] r [tex]\leq[/tex] b) which carries a charge density proportional to the distance from the origin in the region, [tex]\rho[/tex]=kr, for some constant k.

Homework Equations


The Attempt at a Solution


I think I've got the electric field inside the shell figured out, but I could be way off base. I have no idea how to do the rest...
help?

also, sorry, for some reason the <or= sign between a and r isn't working
 
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Remember Gauss' equation for the electric field: E=Q/(4pi e*r^2), where Q is the charge enclosed, pi=3.14159..., e* is a constant (the permittivity of free space), and r is the distance from the "center" of the charge distribution (analogous to center of mass). Inside the spherical shell (r<a<b), E=0 (no charge is enclosed). For a<r<b, the charge enclosed is obtained by integrating the charge density over the volume enclosed. In this case, the charge density is kr, and the differential element of volume is 4(pi)r^2 x incremental change in r (dr). This yields an enclosed charge of (pi)k(r^4-a^4), and substituting into Gauss' equation yields E=(k(r^4-a^4)/(4e*(r^2)). Outside the spherical shell, the enclosed charge is given by Q=(pi)k(b^4-a^4), and this yields E=(k(b^4-a^4))/(4e*(r^2)) for all r such that a<b<= r.
 

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