Positive charges are situated at three corners of a rectangle, as shown in the attachment. Find the electric field at the fourth corner.
the numbers are: bottom left- 3.00 nC bottom right-5.00 nC top right- 6.00 nC
the length of the rectangle is .6 m and the width is .2 m
The Attempt at a Solution
I found all of the forces
F1= 9*10^9 (3*10^-9/.2^2) = 675 n/C
F2= 9*10^9(5*10^-9/.63^2) = 113 n/C
F3= 9*10^9(6*10^-9/.6^2) = 150 n/C
Then I know you have to combine vectors and get the answer, but that's what I'm having trouble doing.
Thanks in advance