Electric field due to point charge

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SUMMARY

The discussion centers on calculating the net electric field at the midpoint between two fixed point charges: particle 1 with a charge of -2.00 x 10^-7 C located at x = 6.0 cm and particle 2 with a charge of +2.00 x 10^-7 C at x = 21.0 cm. The electric field due to each charge is directed towards particle 1 and away from particle 2, leading to a net electric field that is negative, indicating a leftward direction. The participant confirms their understanding of the theory and calculations involved in determining the net electric field using the formula E = kq/r^2.

PREREQUISITES
  • Understanding of electric fields and forces
  • Familiarity with Coulomb's law
  • Knowledge of the formula E = kq/r^2
  • Ability to perform vector addition of electric fields
NEXT STEPS
  • Study the concept of superposition of electric fields
  • Learn about the effects of varying charge magnitudes on electric field strength
  • Explore the implications of charge polarity on electric field direction
  • Investigate the concept of electric field lines and their representation
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding electric fields generated by point charges.

th3plan
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Homework Statement



Two particles are fixed to an x axis: particle 1 charge -2.00x10^-7 at x=6.0cm and particle 2 at 2.00x10^-7 C at x=21.0cm. Midway between the particles, what is there net electric field?

Homework Equations



E=kq/r^2


The Attempt at a Solution



Ok so I drew the picture out, and i know q1 is negative so the electrive field is going towards it to the left, and q2 is + so that means the field is going to the left toward q1, so that means Enet= -E1-E2 , and its negative because there both going to the left? Am i correct on this ? I know the rest of problem is just plugging in numbers, but whant to make sure I am correct on theory. Also let's say that q1 was positive does that mean q1 would go to the left, and q2 field would go to the right, resulting in a zero net force ?
 
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th3plan said:

Homework Statement



Two particles are fixed to an x axis: particle 1 charge -2.00x10^-7 at x=6.0cm and particle 2 at 2.00x10^-7 C at x=21.0cm. Midway between the particles, what is there net electric field?

Homework Equations



E=kq/r^2

The Attempt at a Solution



Ok so I drew the picture out, and i know q1 is negative so the electrive field is going towards it to the left, and q2 is + so that means the field is going to the left toward q1, so that means Enet= -E1-E2 , and its negative because there both going to the left? Am i correct on this ? I know the rest of problem is just plugging in numbers, but whant to make sure I am correct on theory. Also let's say that q1 was positive does that mean q1 would go to the left, and q2 field would go to the right, resulting in a zero net force ?

I'd say you have grasped the concepts. The E field of 0 in your follow up is however only at the mid point which I'm sure you already understand.
 

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