Electric Field from 2.5uC Point Charge at 0.75m

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Homework Help Overview

The problem involves calculating the electric field produced by a 2.5μC point charge at a distance of 0.75m. The relevant equation for this calculation is provided, and there is a focus on understanding the units involved in the result.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the electric field using the formula E = kq/r^2 and expresses concern about unit conversions from Nm²/C² to V/m. Other participants confirm that N/C is equivalent to V/m, addressing the unit concern.

Discussion Status

The discussion includes attempts to clarify unit conversions and confirm the correctness of the calculations. Some participants provide reassurance regarding the units, while the original poster seeks validation of their answer and approach.

Contextual Notes

The original poster indicates a time constraint, emphasizing the urgency of receiving assistance. There is a focus on confirming the correctness of the calculations rather than seeking a complete solution.

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Homework Statement



Find the electric field produced by a 2.5uC point charge at distance of 0.75m.

E = ___ V/m

Homework Equations



E = kq/r^2

The Attempt at a Solution



E = (9x10^9 Nm^2/C^2)(25)/(0.75)^2 = 400 x 10^9

My concern is about the units I am being asked. Since K is using Nm^2/C^2, how do I convert it to V/m IF IT´S CORRECT, of course.

Thanks in advance!
 
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N/C is equivalent to V/m. There is no need to worry about conversions. The units of K cancel with the ones for q and r^2 to give you N/C
 
Hi, thanks for the reply. Does my answer seem correct to you? Am I on the right track?
 
Anyone? Please, time is really short for me and I really need quick help here. Please.
 
I just need a confirmation. I posted the calculus and values. Are they correct?
 

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