Electric Field from 2.5uC Point Charge at 0.75m

AI Thread Summary
To find the electric field produced by a 2.5 µC point charge at a distance of 0.75 m, the formula E = kq/r^2 is used, resulting in E = 400 x 10^9 V/m. There is no need to convert units since N/C is equivalent to V/m, and the units from the equation naturally cancel out. The calculations appear correct based on the provided values. The user seeks confirmation of their answer and the correctness of their approach. Overall, the discussion emphasizes the accuracy of the electric field calculation and unit consistency.
domyy
Messages
196
Reaction score
0

Homework Statement



Find the electric field produced by a 2.5uC point charge at distance of 0.75m.

E = ___ V/m

Homework Equations



E = kq/r^2

The Attempt at a Solution



E = (9x10^9 Nm^2/C^2)(25)/(0.75)^2 = 400 x 10^9

My concern is about the units I am being asked. Since K is using Nm^2/C^2, how do I convert it to V/m IF IT´S CORRECT, of course.

Thanks in advance!
 
Physics news on Phys.org
N/C is equivalent to V/m. There is no need to worry about conversions. The units of K cancel with the ones for q and r^2 to give you N/C
 
Hi, thanks for the reply. Does my answer seem correct to you? Am I on the right track?
 
Anyone? Please, time is really short for me and I really need quick help here. Please.
 
I just need a confirmation. I posted the calculus and values. Are they correct?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top