Electric field inside a parallel plate capacitor

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SUMMARY

The discussion centers on the electric field inside a parallel plate capacitor and the application of Gauss' Law. It is established that while a Gaussian "pillbox" can enclose zero charge, it does not imply that the electric field within that region is zero. The electric field between two oppositely charged plates remains constant due to the contributions from both plates, contrasting with the scenario of a charged spherical shell where the field inside is zero due to the absence of charge. Understanding these distinctions is crucial for correctly applying Gauss' Law.

PREREQUISITES
  • Understanding of Gauss' Law
  • Familiarity with electric fields and charge distributions
  • Knowledge of Gaussian surfaces
  • Concept of electric field behavior in charged spherical shells
NEXT STEPS
  • Study the application of Gauss' Law in various geometries
  • Explore the concept of electric fields in capacitors
  • Learn about the implications of Newton's Shell Theorem
  • Investigate the behavior of electric fields in different charge configurations
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Students and professionals in physics, electrical engineering, and anyone seeking to deepen their understanding of electrostatics and electric field behavior in capacitors.

beardo34
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Ok I took E&M about 3 years ago and decided I needed to review it. I'm up to gauss' law and am getting confused about one thing. If you have two infinitely long oppositely charged plates, solving for the total e field inside is done by making two gaussian surfaces that enclose each plate. Doing this gives the e field to be a constant between the plates.

My question is, why can't I make a gaussian "pillbox" inside the plates and enclosing zero charge and conclude that the flux through that surface is zero since the field goes in one side and leaves through the other? Obviously I'm making a mistake here somewhere because the field in between the plates is NOT zero but I can't figure out what the mistake is.
 
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beardo34 said:
Ok I took E&M about 3 years ago and decided I needed to review it. I'm up to gauss' law and am getting confused about one thing. If you have two infinitely long oppositely charged plates, solving for the total e field inside is done by making two gaussian surfaces that enclose each plate. Doing this gives the e field to be a constant between the plates.

My question is, why can't I make a gaussian "pillbox" inside the plates and enclosing zero charge and conclude that the flux through that surface is zero since the field goes in one side and leaves through the other? Obviously I'm making a mistake here somewhere because the field in between the plates is NOT zero but I can't figure out what the mistake is.

Sure you can do that. The conclusion from Gauss' law is that the pillbox encloses no charge. This is not an unexpected result :smile:
 
Okay but doesn't that mean the electric field inside that pillbox is zero? I am just getting confused because when you have a charged spherical shell, the field inside is zero because there is no charge.
 
beardo34 said:
Okay but doesn't that mean the electric field inside that pillbox is zero? I am just getting confused because when you have a charged spherical shell, the field inside is zero because there is no charge.

No, you can place such a pillbox anywhere in a given electric field where the enclosed charge is zero, yet there is still a field. This tells you that there is no contribution to the field from inside the pillbox.

The Gaussian surface inside a charged spherical shell tells you the same thing -- no enclosed charge and no contribution from inside the pillbox. The field inside the shell is zero for other reasons (see: Newton's Shell Theorem).
 
Ohh okay, that's what I was missing. Thanks a lot!
 

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