Electric Field Intensity at a point due to a infinite line charge

1. Nov 2, 2013

Abel I Daniel

1. The problem statement, all variables and given/known data

Infinite uniform line charges of 5nc/m lie along the (positive and negative) x and y axes in free space.
Find E at :P(0,3,4)

2. Relevant equations
E due to line charge along the Z-axis is given by:
E=(λ/(2∏*ε*r))*ar
where λ=line charge density;ε= permitivity;r=radial distance of point from the line charge;ar=unit vector along the direction of E.

3. The attempt at a solution
Here the line charge lies in z=0 plane right??

2. Nov 2, 2013

haruspex

Yes. Is that all you wanted to know?

3. Nov 2, 2013

rude man

Use Gauss + superposition.

4. Nov 6, 2013

Abel I Daniel

ok,but im trying to do without the help of Gauss law..

5. Nov 6, 2013

Abel I Daniel

so,does it require to take both the cases(along x-axis and y-axis)individually and finally add them ??
If that is the method,we will get an expression of function of x and y(instead of a constant value) right?

6. Nov 6, 2013

rude man

No.
When evaluated at (0,3,4) it will be a constant. The method is immaterial to the answer.

Of course, the field at P(x0, y0, z0) is a function of z0 but not of x0 or y0.