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Electric Field Intensity at a point due to a infinite line charge

  1. Nov 2, 2013 #1
    1. The problem statement, all variables and given/known data

    Infinite uniform line charges of 5nc/m lie along the (positive and negative) x and y axes in free space.
    Find E at :P(0,3,4)

    2. Relevant equations
    E due to line charge along the Z-axis is given by:
    E=(λ/(2∏*ε*r))*ar
    where λ=line charge density;ε= permitivity;r=radial distance of point from the line charge;ar=unit vector along the direction of E.


    3. The attempt at a solution
    Here the line charge lies in z=0 plane right??
     
  2. jcsd
  3. Nov 2, 2013 #2

    haruspex

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    Yes. Is that all you wanted to know?
     
  4. Nov 2, 2013 #3

    rude man

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    Use Gauss + superposition.
     
  5. Nov 6, 2013 #4
    ok,but im trying to do without the help of Gauss law..
     
  6. Nov 6, 2013 #5
    so,does it require to take both the cases(along x-axis and y-axis)individually and finally add them ??
    If that is the method,we will get an expression of function of x and y(instead of a constant value) right?
     
  7. Nov 6, 2013 #6

    rude man

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    No.
    When evaluated at (0,3,4) it will be a constant. The method is immaterial to the answer.

    Of course, the field at P(x0, y0, z0) is a function of z0 but not of x0 or y0.
     
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