- #1
Tiago3434
Hi people, I was reading on my textbook on electromagnetism (Halliday) about using integral to field the electric field of a charged ring (1D) at a point P located on an axis perpendicular to the ring's plane. The ring is uniformly charged. The book (and my professor) both breakdown each element of charge dq into its linear charge density times an element of length, or λds. I'm ok with the math from that point on, but I noticed that you can get the same result just integrating over dq, given that the integral of dq is q. Is my idea wrong, or is there a reason for adding that extra step?
Thanks!
Thanks!