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Electric field outside a gaussian surface

  1. Feb 18, 2016 #1

    If we have a gaussian surface that is placed in a uniform electric field E and encloses 0 charge, what would the E-field at the gaussian surface be? I have assumed the gaussian surface to be cubic surface, and then I have found from Gauss's law that the electric field is zero at the surface even though there is a constant electric field. Can someone please clarify what I am not getting here. Is the electric field in the closed surface integral of Gauss's law is only related to the enclosed charge or is related to outer charges.

  2. jcsd
  3. Feb 18, 2016 #2
    It is only related to the enclosed charge. Think about it this way. The field lines from unenclosed charge that enter the Gaussian surface will exit it eventually, producing no net flux.
  4. Feb 18, 2016 #3
    So gauss's law provides information related to the enclosed charge, but nothing about electric field and charge magnitude outside the gaussian surface.
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