# Electric field outside a gaussian surface

## Main Question or Discussion Point

Hello

If we have a gaussian surface that is placed in a uniform electric field E and encloses 0 charge, what would the E-field at the gaussian surface be? I have assumed the gaussian surface to be cubic surface, and then I have found from Gauss's law that the electric field is zero at the surface even though there is a constant electric field. Can someone please clarify what I am not getting here. Is the electric field in the closed surface integral of Gauss's law is only related to the enclosed charge or is related to outer charges.

Thanks