- #1

- 50

- 2

## Main Question or Discussion Point

Hello

If we have a gaussian surface that is placed in a uniform electric field E and encloses 0 charge, what would the E-field at the gaussian surface be? I have assumed the gaussian surface to be cubic surface, and then I have found from Gauss's law that the electric field is zero at the surface even though there is a constant electric field. Can someone please clarify what I am not getting here. Is the electric field in the closed surface integral of Gauss's law is only related to the enclosed charge or is related to outer charges.

Thanks

If we have a gaussian surface that is placed in a uniform electric field E and encloses 0 charge, what would the E-field at the gaussian surface be? I have assumed the gaussian surface to be cubic surface, and then I have found from Gauss's law that the electric field is zero at the surface even though there is a constant electric field. Can someone please clarify what I am not getting here. Is the electric field in the closed surface integral of Gauss's law is only related to the enclosed charge or is related to outer charges.

Thanks