Electric Fields and Kinetic Energy of protons

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SUMMARY

The discussion focuses on calculating the electric field required to stop protons with a kinetic energy of 3.25 x 10^-15 J over a distance of 1.25 m. The relevant equations include the electric force equation, Felectric = kC (q*q/r^2), and the relationship between work done by the electric force and kinetic energy. The solution involves determining the final kinetic energy and applying the work-energy principle to find the necessary electric field strength.

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hirschy
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Homework Statement



Each of the protons in a particle beam has a kinetic energy of 3.25 x 10^-15 J. What are the magnitude and direction of the electric field that will stop these protons in a distance of 1.25 m?


Homework Equations



Felectric = kC (q*q/r^2)
Electric Field= Felectric/q
Electric Field= kC (q/r^2)
Velocityfinal= velocityInitial + a*t
Velocityfinal^2 = VelocityInitial^2 + 2a(d)



The Attempt at a Solution



I need help with this.
 
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Work done by the electric force = change in the KE.
Initial KE is given. Final KE = ...?
Work done by the electric force F = ...?
And as you have stated E = f/q.
Now try.
 

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