Electric Potential and Wave Nature of Matter

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quicksilver123
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Homework Statement


An electric potential difference accelerates electrons from rest position towards a screen.
Just before striking the screen, the electrons have a wavelength of 1.0*10^-11 m
Find the electric potential difference.

Homework Equations



p=h/λ
ΔEK=qΔV

The Attempt at a Solution



p=h/λ
mv=h/λ
v=h/λm
v=(6.63*10^-34)/((1.0*10^-11)(9.11*10^-31))
v=72777167.95 m/s

ΔEK=qΔV
EK2-EK1=eΔV
0.5(9.11*10^-31)(72777167.95)^2 - 0.5(9.11*10^-31)(0)^2 = eΔV
ΔV=0.5(9.11*10^-31)(72777167.95)^2 / e
ΔV=15078.51948 V

Is this correct? (other than significant digits)
 
Last edited:
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Once again your v=(6.63*10^-34) / ( (1.0*10^-11) * (9.11*10^-31) )equation needs some parens

and your v result needs to be significant figure adjusted to be 7.28 x 10^7 m/s

similarly for the delta v result.

Again the physics looks right but someone at PF needs to second it for me.
 
fixed.

the question wasn't asking for velocity so i didn't round it in order to get a more accurate result for electric potential difference