Electric Potential and Wave Nature of Matter

Click For Summary
SUMMARY

The discussion centers on calculating the electric potential difference required to accelerate electrons to a specific wavelength of 1.0 x 10^-11 m. Using the de Broglie wavelength formula \( p = \frac{h}{\lambda} \) and the kinetic energy equation \( \Delta EK = q \Delta V \), the calculated electric potential difference is approximately 15078.52 V. The velocity of the electrons was determined to be 7.28 x 10^7 m/s after adjusting for significant figures. The physics principles applied in the calculations were confirmed to be correct.

PREREQUISITES
  • Understanding of de Broglie wavelength and momentum
  • Familiarity with kinetic energy equations
  • Knowledge of electric potential and charge relationships
  • Basic proficiency in significant figures and unit conversions
NEXT STEPS
  • Study the de Broglie wavelength concept in quantum mechanics
  • Learn about the relationship between electric potential and kinetic energy
  • Explore advanced topics in electron behavior in electric fields
  • Review significant figures and their importance in physics calculations
USEFUL FOR

Physics students, educators, and anyone interested in the wave-particle duality of matter and the principles of quantum mechanics.

quicksilver123
Messages
173
Reaction score
0

Homework Statement


An electric potential difference accelerates electrons from rest position towards a screen.
Just before striking the screen, the electrons have a wavelength of 1.0*10^-11 m
Find the electric potential difference.

Homework Equations



p=h/λ
ΔEK=qΔV

The Attempt at a Solution



p=h/λ
mv=h/λ
v=h/λm
v=(6.63*10^-34)/((1.0*10^-11)(9.11*10^-31))
v=72777167.95 m/s

ΔEK=qΔV
EK2-EK1=eΔV
0.5(9.11*10^-31)(72777167.95)^2 - 0.5(9.11*10^-31)(0)^2 = eΔV
ΔV=0.5(9.11*10^-31)(72777167.95)^2 / e
ΔV=15078.51948 V

Is this correct? (other than significant digits)
 
Last edited:
Physics news on Phys.org
Once again your v=(6.63*10^-34) / ( (1.0*10^-11) * (9.11*10^-31) )equation needs some parens

and your v result needs to be significant figure adjusted to be 7.28 x 10^7 m/s

similarly for the delta v result.

Again the physics looks right but someone at PF needs to second it for me.
 
fixed.

the question wasn't asking for velocity so i didn't round it in order to get a more accurate result for electric potential difference
 

Similar threads

  • · Replies 34 ·
2
Replies
34
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
8K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 16 ·
Replies
16
Views
8K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K