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pbonnie
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Homework Statement
In a TV tube, an electric potential difference accelerates electrons from a rest position towards a screen. Just before striking the screen, the electrons have a wavelength of [itex]1.0 x 10^{-11} m [/itex]. Find the electric potential difference.
Homework Equations
[itex]λ = h/mv [/itex]
[itex] ΔE_k = qΔV [/itex]
The Attempt at a Solution
[itex] v = h/λm = (6.63x10^{-34}Js)/(1.0x10^{-11}m)(9.11x10^{-31})[/itex]
[itex] = 7.3 x 10^7 m/s[/itex]
I rearranged the second equation to solve for ΔV
[itex] ΔV = ((1/2)(9.11x10^{-31}kg)(7.3x10^7m/s))/(1.60 x 10^-19c)[/itex]
[itex] = 2.1 x 10^{-4} V[/itex]
I was just wondering if someone could let me know if I'm doing this right? Sorry for not using latex properly, I'm not really sure how to make fractions.
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