Electric Potential Difference during thunder storm

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SUMMARY

During a thunderstorm, the movement of water molecules creates friction, resulting in the bottom of clouds becoming negatively charged. This leads to an electric potential difference between the cloud and the ground, calculated to be 4.5 x 10^8 V when the electric field exceeds 3.0 x 10^6 N/C. When 6.24 x 10^18 electrons move from the ground to the cloud, they represent an electric potential energy of -4.5 x 10^8 J. Electrons moving from the cloud to the ground lose energy as they approach the positive charge of the ground.

PREREQUISITES
  • Understanding of electric fields and potential difference
  • Familiarity with basic electrostatics concepts
  • Knowledge of charge quantization and electron properties
  • Ability to apply equations related to electric potential and energy
NEXT STEPS
  • Study the principles of electric fields and potential difference in electrostatics
  • Learn about charge separation and its role in lightning phenomena
  • Investigate the mechanics of lightning strikes and energy dissipation
  • Explore the differences between capacitors and natural charge separation in storms
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Students studying physics, educators teaching electrostatics, meteorologists interested in storm phenomena, and anyone seeking to understand the mechanics of lightning and electric potential differences.

EmilyBergendahl
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Homework Statement


During a thunder storm, movement of water molecules within clouds creates friction which causes the bottom of the clouds to become negatively charged. This means that the bottom of the cloud and the ground begin to act like parallel plates. Once the electric field between the clouds and the ground becomes larger than 3.0 x 10^6 N/C, lightning will strike.
a. If the bottom of the cloud is 150 m above the ground, determine the electric potential difference between the ground and the cloud.
b. Say 6.24 x 10^18 electrons move between the ground and the cloud during a lightning strike. How much electric potential energy does this represent? Are the electrons gaining or losing energy?

Homework Equations


E = V/d
q = Ne
V = E_E/q

The Attempt at a Solution


a.
E = V/d
V = Ed
V = (3.0 x 10^6 N/C)(150 m)
V = 4.5 x 10^8 V

b.
q = Ne
q = (6.24 x 10^18)(-1.6 x 10^19)
q = -0.9984 C
q = -1.0 C

V = E_E/q
E_E = Vq
E_E = (4.5 x 10^8 V)(-1.0 C)
E_E = -4.5 x 10^8 J

How can I tell if the electrons are gaining or losing energy?
 
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Math looks good.

Where are the electrons after the strike? Does this represent a change in the potential energy of the electrons? If so, in which direction?
 
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Thank you for the response!

I'm not sure if I'm understanding it completely, but if the electrons are moving from the ground (positive plate) to the cloud (negative plate), the electrons would be gaining energy?
 
EmilyBergendahl said:
but if the electrons are moving from the ground (positive plate) to the cloud (negative plate)

EmilyBergendahl said:
which causes the bottom of the clouds to become negatively charged
 
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Okay. If the bottom of the clouds are negatively charged, that means that an excess of electrons is present. If more electrons move into the clouds, the electrons in the cloud are gaining energy?
 
I don't think I'm visualizing this properly...
 
EmilyBergendahl said:
Okay. If the bottom of the clouds are negatively charged, that means that an excess of electrons is present. If more electrons move into the clouds, the electrons in the cloud are gaining energy?
Well, I don't know the exact mechanism of lightning phenomenon but from this,
EmilyBergendahl said:
During a thunder storm, movement of water molecules within clouds creates friction which causes the bottom of the clouds to become negatively charged. This means that the bottom of the cloud and the ground begin to act like parallel plates.
I imagine the clouds are negatively charged before the lightning strike. This makes the ground positive w.r.t clouds.
 
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EmilyBergendahl said:
I don't think I'm visualizing this properly...
If the clouds are negative and ground is positive, how will be the flow of charge?
 
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In the strike, the electrons will be moving from the cloud to the ground. Therefore, the electrons in the cloud are losing energy?
 
  • #10
EmilyBergendahl said:
In the strike, the electrons will be moving from the cloud to the ground. Therefore, the electrons in the cloud are losing energy?
Yes. When a -ve charge is brought closer to a +ve charge, it loses energy and when it is taken away from the +ve charge, it gains energy.
 
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  • #11
Thank you so much again!
 
  • #12
cnh1995 said:
Yes. When a -ve charge is brought closer to a +ve charge, it loses energy and when it is taken away from the +ve charge, it gains energy.
Note that this is about potential energy of the electrons.
 
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  • #13
EmilyBergendahl said:
Thank you for the response!

I'm not sure if I'm understanding it completely, but if the electrons are moving from the ground (positive plate) to the cloud (negative plate), the electrons would be gaining energy?
Yes. Potential energy. As the cloud becomes more and more negatively charged it takes more and more energy to move an electron from the ground to the cloud.

When lightning finally strikes the potential energy is dissipated into light, sound and heat, and who knows what else (e.g. flying debris).

EDIT: the analogy to a capacitor with parallel plates is actually not good. In the capacitor the plates assume a NET charge, in lightning neither the cloud nor the Earth do. The movement of the cloud forces separation of charges so that the bottom of the cloud becomes - and the proximate Earth is induced +. I'm not sure that the electrons actually travel from the cloud to ground as the problem postulates. This is actually a not well understood science even today as I understand it.

.
 
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