There are four spheres arranged as the four corners of a square, each sphere having a charge of 10 nC and seperated from each other by a distance of 1 cm. The four 1.0 g spheres are released simultaneously and allowed to move away from each other. What is the speed of each sphere when they are very far apart? (see attached figure).(adsbygoogle = window.adsbygoogle || []).push({});

I know that for kinetic and potential energy deltaK = -deltaU

K_f - K_i = U_f - U_i

K_i = 0

U_f = 0

K_f = U_i

First I found the total potential energy of the system. U = (q_1*q_2*k)/r. Since all charges are the same, the interaction of any two charges is q^2 (where q^2 = 1*10^-16). The six interactions between the charges produce the following calculation for potential energy:

U = K { q^2/r + q^2/r + q^2/r +q^2/r + q^2/sqrt(2)r + q^2/sqrt(2)r }

U = K { 4q^2/r + 2q^2/sqrt(2)r) }

Plugging in 10^-8 for q, and 0.01 for r, gets

U = K (5.414*10^-14)

U = 0.000487

Since U_i = K_f,

0.000487 = 0.5mv^2

The mass of the spheres is 1g (0.001 kg)

0.973 = v^2

v = 0.987, which should be the final speed of each sphere. This is incorrect, though.

Could somebody please tell me where I went wrong? Thank you for your time.

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# Homework Help: Electric potential of four charges

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