Electric Potential Problem - Fixed Template

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Zackkkkkk
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Homework Statement


An electric charge q1 (-6e) is located at the origin. A second electric charge q2 (+2e) is located a distance "d" from the origin. In terms of "d", what is the distance "x" from q1 where the net electric potential is zero? Assume for this problem that x<d.2.Relevant equations
I need a solid explanation on how to do this problem properly. I have a strong feeling that this can't be right (my attempt). I need to be able to understand and work problems like this for my upcoming exam. Any help would be appreciated.

The Attempt at a Solution


Vtotal = V1 + V2.
If Vtotal = 0 then V1+V2=0.
V1-V2
kq1/x = - kq2/d-x
q1/x = - q2/d-x
(q1(d-x))/(-q2) = x
3(d-x) = x
3d = 4x
(3d/4) = x[/B]
 
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Zackkkkkk said:

Homework Statement


An electric charge q1 (-6e) is located at the origin. A second electric charge q2 (+2e) is located a distance "d" from the origin. In terms of "d", what is the distance "x" from q1 where the net electric potential is zero? Assume for this problem that x<d.2.Relevant equations
I need a solid explanation on how to do this problem properly. I have a strong feeling that this can't be right (my attempt). I need to be able to understand and work problems like this for my upcoming exam. Any help would be appreciated.

The Attempt at a Solution


Vtotal = V1 + V2.
If Vtotal = 0 then V1+V2=0.
V1-V2 [/B]##\quad \quad ## Looks like a missing "=" sign, V1 = -V2
kq1/x = - kq2/(d-x)
q1/x = - q2/(d-x)
(q1(d-x))/(-q2) = x
3(d-x) = x
3d = 4x
(3d/4) = x
Other than what appears to be a typo above, and the lack of some needed sets of parentheses, that looks good.

I'm pretty sure that the final answer is correct.
 
SammyS said:
Other than what appears to be a typo above, and the lack of some needed sets of parentheses, that looks good.

I'm pretty sure that the final answer is correct.
Thank you for your input, friend.