Cylindrical shell- electric potential problem

In summary, we have a very long insulating cylindrical shell with a radius of 6.40 cm and a linear charge density of 8.90μC/m spread uniformly over its outer surface. We are asked to find the voltmeter reading when it is connected between the surface of the cylinder and a point 4.00 cm above the surface. By using the formula V=λk*ln([r+x]/r), we get a result of 3.89e4, which is half of the actual answer of 7.78e4. Possible sources of error could be the calculation of the linear charge density or the use of the formula for electric field according to Gauss' Law.
  • #1
giacomh
36
0
A very long insulating cylindrical shell of radius 6.40 cm carries charge of linear density 8.90μC/m spread uniformly over its outer surface. What would a voltmeter read if it were connected between the surface of the cylinder and a point 4.00 cmabove the surface?

λ=dq/dr
V=k∫dq/r


V=λk*ln([r+x]/r)
V=(8.9e-6)*9e9*ln(.104/.064)
V=3.89e4


The actual answer is 7.78e4 (twice my answer). I can't figure out what's wrong with my integral to make the answer half of what it should be. Thanks!
 
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  • #2
giacomh said:
A very long insulating cylindrical shell of radius 6.40 cm carries charge of linear density 8.90μC/m spread uniformly over its outer surface. What would a voltmeter read if it were connected between the surface of the cylinder and a point 4.00 cmabove the surface?

λ=dq/dr
V=k∫dq/rV=λk*ln([r+x]/r)

λ is the linear charge density, λ=dq/dL.
Check also the formulae for V. What is the electric field around a very long cylindrical shell according to Gauss' Law?

ehild
 

1. What is a cylindrical shell-electric potential problem?

A cylindrical shell-electric potential problem involves determining the electric potential at a point near or inside a cylindrical shell with a given charge distribution. This is a common problem in electrostatics and is used to understand the behavior of electric fields and charges in cylindrical systems.

2. How do you solve a cylindrical shell-electric potential problem?

To solve a cylindrical shell-electric potential problem, you can use the formula V = kQ/r, where V is the electric potential, k is the Coulomb's constant, Q is the charge of the shell, and r is the distance from the point to the center of the shell. You can also use the superposition principle to add the potentials from different parts of the shell.

3. What are some real-life applications of cylindrical shell-electric potential problems?

Cylindrical shell-electric potential problems have several real-life applications. They are used in the design and analysis of cylindrical capacitors, such as those found in electronic devices. They are also used in the study of electric fields and their effect on charged particles in cylindrical systems, which can be applied to technologies like particle accelerators and medical imaging devices.

4. What assumptions are made when solving a cylindrical shell-electric potential problem?

When solving a cylindrical shell-electric potential problem, it is assumed that the charge distribution on the shell is continuous and the shell is infinitely thin. Additionally, it is assumed that there are no other charges or external electric fields present that may affect the system.

5. What are the units for electric potential in a cylindrical shell-electric potential problem?

The units for electric potential in a cylindrical shell-electric potential problem are volts (V). This is the same unit used for electric potential in any other electrostatics problem. It represents the amount of work needed to move a unit positive charge from infinity to a point near or inside the cylindrical shell.

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