Electrical Engineering - Increasing the Time an Alarm will Buzz

AI Thread Summary
The discussion centers on a homework problem involving the design of an alarm that buzzes for approximately six seconds. The initial attempt resulted in a buzz duration of only 1.5 seconds, prompting the need for assistance. Key equations used include τ = RC and V = V0e-t/τ, with calculations involving Thevenin's voltage and resistance. Participants suggest incorporating an NPN transistor for better circuit control and discuss the configuration of the buzzer and window switch. Clarifications are sought regarding voltage values and the circuit's operational parameters to achieve the desired buzzing duration.
Mosaness
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Homework Statement



The problem is to create a small alarm that will buzz approximately 6 seconds before it stops buzzing. I managed to create a working alarm, only problem is mines will buzz for around 1.5 seconds not six.

Homework Equations



τ = RC
V = V0e-t/τ


The Attempt at a Solution



Req. = 400Ω + (80Ωll100Ω) ≈ 444.44 Ω
VTH = 6V * (400Ω/480Ω) = 5V

Substituting this into equation #2 above gives 5V = 9V*e-6/τ
Solving for T yields:

Actually, I just lost myself in my work. Can someone help me.
 

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Mosaness said:

Homework Statement



The problem is to create a small alarm that will buzz approximately 6 seconds before it stops buzzing. I managed to create a working alarm, only problem is mines will buzz for around 1.5 seconds not six.

Homework Equations



τ = RC
V = V0e-t/τ


The Attempt at a Solution



Req. = 400Ω + (80Ωll100Ω) ≈ 444.44 Ω
VTH = 6V * (400Ω/480Ω) = 5V

Substituting this into equation #2 above gives 5V = 9V*e-6/τ
Solving for T yields:

Actually, I just lost myself in my work. Can someone help me.

Where is the buzzer? How is it turned on and off?
 
berkeman said:
Where is the buzzer? How is it turned on and off?

The buzzer has a resistance of 400 ohms so that's what was used. It is turned on when someone opens the window.
 
Mosaness said:
The buzzer has a resistance of 400 ohms so that's what was used. It is turned on when someone opens the window.

And how do you intend to connect the buzzer and window switch to your circuit that you've drawn? How does the circuit reset when the window is later closed?

BTW, it would be better to use an NPN transistor as part of the circuit that drives the buzzer. Do you know why?
 
berkeman said:
And how do you intend to connect the buzzer and window switch to your circuit that you've drawn? How does the circuit reset when the window is later closed?

BTW, it would be better to use an NPN transistor as part of the circuit that drives the buzzer. Do you know why?

Oh...the class I am taking is a basic class. I've never even heard of a NPN transistor. I made a PSPICE design. The switch was connected right next to the 100Ω.
 
I did a calculation earlier but I slightly messed up. I obtained Vthevenin by the equation 18V * 80/180 --> which gave me 8V.

I then set that so:

8V = 18V*e^-6/tau and solved for tau, which gave me tau = 7.3989

Using that tau I solved for C, which gave me C = .0166 F
 
Mosaness said:
I did a calculation earlier but I slightly messed up. I obtained Vthevenin by the equation 18V * 80/180 --> which gave me 8V.

I then set that so:

8V = 18V*e^-6/tau and solved for tau, which gave me tau = 7.3989

Using that tau I solved for C, which gave me C = .0166 F

Why not just use a "normally open" (NO) switch in series with the buzzer, a resistor and a cap? Or even just the switch, buzzer and cap...?
 
berkeman said:
Why not just use a "normally open" (NO) switch in series with the buzzer, a resistor and a cap? Or even just the switch, buzzer and cap...?

Well I just went on the way I know a few people did. And that seems to be giving me an appropriate time...
 
Mosaness said:
Req. = 400Ω + (80Ωll100Ω) ≈ 444.44 Ω
VTH = 6V * (400Ω/480Ω) = 5V

Substituting this into equation #2 above gives 5V = 9V*e-6/τ
Req I understand. VTH I don't.

According to your schematic, you are using a supply voltage of 18V. Correct? So where did the "6V" figure come from? What is special about the "5V" figure? Where did the "9V" come from? What operating parameter of the buzzer are you working with, in trying to determine how long it will actually "buzz"?
 
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