Electrical potential energy: 3 charges in a line

AI Thread Summary
The discussion centers on calculating the electric potential energy (EPE) of three charges arranged in a line. The initial attempt to calculate EPE using the formula EPE = kq / r was incorrect, as the proper formula is U = k(q_a q_b) / r_ab, which accounts for the interaction between pairs of charges. Participants noted the importance of using the correct distances between charges, rather than their positions, to compute the potential energy accurately. Additional information regarding the specific charges of q1, q2, and q3 is also necessary for a complete solution. Correcting these aspects should lead to a valid answer for the potential energy of the system.
alicemunro
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Homework Statement



A positive charge, q1 is at (-20cm,0). An equal and opposite charge q2 is at (20cm, 0). A positive charge q3, equal to q1, is placed at (60cm,0). What is the potential energy of the three charges??


Homework Equations



EPE= kq / r


The Attempt at a Solution


EPE = k( (5 X 10^-9)/.2) + (5 X 10^-6)/.6) - (5 X 10^-6)/.2))
= wrong answer
 
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alicemunro said:

Homework Statement



A positive charge, q1 is at (-20cm,0). An equal and opposite charge q2 is at (20cm, 0). A positive charge q3, equal to q1, is placed at (60cm,0). What is the potential energy of the three charges??


Homework Equations



EPE= kq / r


The Attempt at a Solution


EPE = k( (5 X 10^-9)/.2) + (5 X 10^-6)/.6) - (5 X 10^-6)/.2))
= wrong answer
It looks like you have additional information to provide such as the charges of q1,q2, q3 also your equation for electric potential energy is incorrect should be:
U = k \frac{q_a q_b}{r_{ab}}
Finally I need to note that r is not the position but rather the relative distance between charges a and b. With these adjustments the answer should clear up a bit
 
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