Electricffiledcalcuate escape speed

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    Escape Speed
AI Thread Summary
The discussion focuses on calculating escape speed using electric field equations. The relevant equations include kinetic energy (KE = 1/2 mv^2) and electric potential energy (Ue = Eqs). The user attempts to solve the problem by setting final potential and kinetic energy to zero, leading to the equation v = (sEqs/m)^(1/2). The final answer for escape speed is confirmed to be 2.3 x 10^6 m/s. The thread highlights the importance of understanding energy conservation in electric fields.
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electricffiled..calcuate escape speed! urgent please help

Homework Statement



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Homework Equations



ke=1/2mv^2
Ue=Eqs
E=kq/r^2

The Attempt at a Solution


Uf+kf=Ki+Ui

Uf=0 and Kf=0

so -Ui=Ki
Eqs=1/2(mv^2)

v=(sEqs/m)^1/2 after this no clue i got lost help please
 
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sry guys is the answer 2.3x10^6m/s
 


Yes, it is.

ehild
 
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