Electricity Problems - conductive spheres

AI Thread Summary
Sphere X, initially charged to 10,000 volts, is connected to sphere Y, allowing charge to redistribute until both spheres reach the same potential. After disconnecting and connecting sphere Y to sphere Z, sphere Z will also equalize its potential with sphere Y. The potential on sphere Z is determined to be 5,000 volts, and the charge on sphere Z is calculated to be +¼ Q. The process illustrates the principles of charge distribution and potential equalization in conductive spheres. Understanding these concepts is crucial for solving similar electrostatics problems.
big_boi
Messages
3
Reaction score
0

Homework Statement




Initially, metal sphere X is charged to an electric potential of 10,000 volts, with a total charge on its surface of +Q. Metal spheres Y and Z are initially uncharged. Spheres Y and Z are the same size as sphere X. All three spheres are held by insulated stands.


6. Sphere X is connected by a conducting wire to sphere Y. The wire is then removed and used to connect sphere Y and Z. After the wire is again removed, what is the potential on sphere Z?
a. 10,000 V
b. 5,000 V
c. 2,500 V
d. 1,250 V
e. 0
7. What is the charge on sphere Z after the procedure described in problem 6?
a. +Q
b. + ½ Q
c. + ¼ Q
d. + 1/3 Q
e. –Q


Homework Equations





The Attempt at a Solution



Is it A and C?
 
Physics news on Phys.org
Connecting two spheres will cause charge flow till both have equal potentials. In short answer is C and C.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top