Electricity-Resistance Question

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SUMMARY

The discussion centers on calculating the required value of a second resistor to achieve a specific voltage drop across a combination of resistors in parallel. The student needs a voltage drop of 5.0V with a total current of 2.0mA. The solution reveals that the second resistor should be 6.7 kOhms, resulting in an effective resistance of 2.5 kOhms for the combination. The calculations utilize Ohm's Law and the formula for equivalent resistance in parallel circuits.

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Homework Statement



A Student needs to construct a circuit in which there is a voltage drop of 5.0v across a resistance combination, and a total current of 2.0mA flowing through the combination. She has a 4000 Ohm ( 4.0kOhm) resistor which she wants to use and proposes to add another resistor in parallel with it.


Homework Equations



a) What value should she use for the second resistor

b) Determine the effective resistance of the combination

The Attempt at a Solution



I have no idea how to work this out. The answers are

a) 6.7 kOhms

b) 2.5 kOhms

I just need to know how to get to that answer
 
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Voltage drop across the "equivalent" resistance, meaning the resistance shown by the 2 resistances in parallel, equals 5V.

V = I*R => R = V/I

R = 5V/2mA = 2,500 OhmsNow this R is the equivalent resistance R_eq, which can be found by:

1/R_eq = 1/R1 + 1/R2

or after rearranging: R_eq = R1*R2/(R1+R2) , where you know one of the resistors (R1 = 4 kOhm).
 

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