Electricity Sparks: Finding the Voltage Difference for a 0.2 cm Jump

Click For Summary

Homework Help Overview

The discussion revolves around calculating the minimum voltage difference required for a spark to jump a distance of 0.2 cm between a finger and a doorknob, within the context of electricity and electrostatics.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formula V=Ed and question the values used for the electric field strength (E). There is a focus on the breakdown voltage for air and the correct conversion of distance from centimeters to meters.

Discussion Status

Some participants have provided insights into the appropriate value for the electric field strength and have questioned the original poster's calculations. There appears to be a productive exchange regarding the correct parameters to use, although no consensus has been reached on the final calculation.

Contextual Notes

Participants note potential confusion regarding unit conversions and the appropriate values for electric field strength, which may impact the calculations being discussed.

whoknows12345
Messages
9
Reaction score
0
Suppose that after walking across a carpeted floor you reach for a doorknob, and just before you touch it a spark jumps 0.2 cm between your finger and the doorknob. Find the minimum voltage difference between your finger and the doorknob for this to occur.

I did V=Ed

which I plugged in (8.85 x 10^-12)(.2 x 10^-3) and I got this wrong. What am I doing wrong?
 
Physics news on Phys.org
whoknows12345 said:
Suppose that after walking across a carpeted floor you reach for a doorknob, and just before you touch it a spark jumps 0.2 cm between your finger and the doorknob. Find the minimum voltage difference between your finger and the doorknob for this to occur.

I did V=Ed

which I plugged in (8.85 x 10^-12)(.2 x 10^-3) and I got this wrong. What am I doing wrong?
How are you determining what E is? It seems to be several orders of magnitude out. I think the breakdown E for air is in the order of a few million volts/metre. Also you appear to be using .2 mm not .2 cm.

AM
 
so it would be ((8.85 x 10^-12)/1.00059) x (2.2 x 10^-2) which is 1.769e-14?
 
nevermind, i got it. i was using the wrong E, E was 3,000,000
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
Replies
2
Views
1K
Replies
19
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
7K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 16 ·
Replies
16
Views
1K