Electrochemical Cell | 75W Bulb | 50min | 12V Battery

AI Thread Summary
To determine the energy required to power a 75.0 W light bulb for 50 minutes using a 12.0 V battery, the calculation involves converting time into seconds and applying the power formula. The total time is 3000 seconds (50 minutes x 60 seconds). Since 1 watt equals 1 joule per second, the energy can be calculated as 75.0 J/s multiplied by 3000 seconds, resulting in 225,000 joules. The key is to ensure the seconds cancel out to isolate joules in the final calculation. This approach confirms that 225,000 joules are needed to keep the bulb burning for the specified duration.
nicolew12
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Homework Statement



A 75.0-W light bulb is powered by connecting it to a standard 12.0 V auto lead-storage battery. How much energy (J) is required to keep the bulb burning for 50.0 continuous minutes ?
Assume 100 percent efficency.

Homework Equations



1 watt = 1 J/s
1 J = 1 C x 1 V

The Attempt at a Solution



(50min/12v)(60second/min)(75J/second)

I am confused about how to get Joules by itself
 
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Use the fact that 75.0 W is 75.0 J/s. If you can do something to cancel the s in 75.0 J/s, you will have the energy in Joules.
 
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